[英]inferring types from an Error throwing function in Typescript?
[英]TypeScript Wrapper Function Inferring Types
我对与数据库操作相关的函数使用了一个小实用程序/包装器函数。 它应该采用类型为Promise<PromiseReturnType<GENERIC>>
的特定函数fn
,然后在执行它之前做一些事情(这里:检查连接):
// File `A.ts`
type PromiseReturnType<T = undefined> = {success: boolean, response: T }
const DatabaseOperation = <Fn extends (...args: any) => Promise<PromiseReturnType<Data>>, Data>(fn: (...args: any) => Promise<PromiseReturnType<Data>>) => {
return async function (...args: Parameters<Fn>): Promise<PromiseReturnType<Data>> {
if (!isConnected) return Promise.reject({ success: false, response: new Error("Not connected to the Database!") })
return await fn(...args)
}
}
然后我像这样使用它:
// File `B.ts`
const dbOperation = async (myArg: number): Promise<PromiseReturnType<string> => {
return Promise.resolve({ success: true, response: `hello world ${myArg}` })
}
export default DatabaseOperation<typeof dbOperation, string>(dbOperation)
除了无法推断返回类型外,它工作正常。 它将是Promise<any>
除了Promise<PromiseReturnType<string>>
。
使用新包装的函数将如下所示:
import dbOperation from "B.ts"
(function () {
await dbOperation() // Type: dbOperation(myArg: number): Promise<any>
})()
关于如何解决这个问题或总体上更好地实施这个问题的任何建议?
感谢您的帮助,谢谢。
你快到了:
declare var isConnected: boolean;
type PromiseReturnType<T = undefined> = { success: boolean, response: T }
const DatabaseOperation = <Data, Fn extends (...args: any[]) => Promise<PromiseReturnType<Data>>,>(fn: (...args: any[]) => Promise<PromiseReturnType<Data>>) => {
return async function (...args: Parameters<Fn>): Promise<PromiseReturnType<Data>> {
if (!isConnected) return Promise.reject({ success: false, response: new Error("Not connected to the Database!") })
return await fn(...args)
}
}
const dbOperation = (myArg: number): Promise<PromiseReturnType<string>> =>
Promise.resolve({ success: true, response: `hello world ${myArg}` })
const fn = DatabaseOperation(dbOperation)
const result = fn(42) // Promise<PromiseReturnType<string>>
你应该让...args
成为一个数组any[]
而不是any
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