[英]How to sort object of array with external condition and the property of object?
[英]How to sort array of object with a condition?
let array = [
{
"vendorBidId": null,
"participantName": "test+10@mail.com",
"bidAmount": 0,
"productionRate": null,
"bidTime": null,
"isYou": false,
"awarded": false
},
{
"vendorBidId": 16,
"participantName": "test+2@mail.com",
"bidAmount": 131,
"productionRate": 131,
"bidTime": "2021-09-18T08:11:21.295",
"isYou": true,
"awarded": false
},
{
"vendorBidId": 20,
"participantName": "test@mail.com",
"bidAmount": 30,
"productionRate": 30,
"bidTime": "2021-0a-18T08:11:21.295",
"isYou": true,
"awarded": false
},
{
"vendorBidId": 30,
"participantName": "test@mail.com",
"bidAmount": 40,
"productionRate": 40,
"bidTime": "2021-0a-18T08:11:21.295",
"isYou": true,
"awarded": false
},
{
"vendorBidId": null,
"participantName": "test+10@mail.com",
"bidAmount": 0,
"productionRate": null,
"bidTime": null,
"isYou": false,
"awarded": false
},
{
"vendorBidId": 40,
"participantName": "test@mail.com",
"bidAmount": 50,
"productionRate": 50,
"bidTime": "2021-0a-18T08:11:21.295",
"isYou": true,
"awarded": false
}
]
我想按升序(bidAmount)对这个数组进行排序,如果 vendorBidId 为空,则不要排序保留在底部。
我试过这样
array.sort((a,b) => parseFloat(a.bidAmount) - parseFloat(b.bidAmount)).map((ele) => console.log(ele.bidAmount))
我需要一个像 30,40,50,131,0,0 这样的输出,但对于我上面的代码,它只会排序。 我尝试使用 reduce 但这不能正常工作
array.sort((a,b) => {
const n = a.vendorBidId === null ? Number.MAX_VALUE : a.bidAmount;
const m = b.vendorBidId === null ? Number.MAX_VALUE : b.bidAmount;
return n - m;
});
// "2.5" + "3.5" = "2.53.5"
// "2.5" - "3.5" = -1
以 DragatS 共享的内容为基础......只需像这样映射 sort() 的结果即可得到 [30,40,50,131,0,0] 的结果
const res = array
.sort((a, b) => {
const n = a.vendorBidId === null ? Number.MAX_VALUE : a.bidAmount;
const m = b.vendorBidId === null ? Number.MAX_VALUE : b.bidAmount;
return n - m;
})
.map(item => item.bidAmount);
console.log(res);
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.