无法弄清楚 MYSQL 查询的问题

Question

嘿伙计们我有这个查询

SELECT SUM(body), SUM(mice), SUM(sety) FROM
(
  SELECT sum(body1) as body, sum(mice1) as mice, sum(sety1) as sety from utkani where hrac1 in(select hrac1 from skupina where id=66) 
  UNION ALL
  SELECT sum(body2) as body, sum(mice2) as mice, sum(sety2) as sety from utkani where hrac2 in(select hrac1 from skupina where id=66) 
)

我收到错误：

#1248 - Every derived table must have its own alias

你能帮我解决这个问题吗？

Answer 1

一个 deivd 表是你在第一个FROM子句之后的内容

因为它是一个 tbale，它必须是一个像 utkani 这样的名字，但正如你所看到的，一个 t1 就足够了

SELECT SUM(body), SUM(mice), SUM(sety) FROM
(
  SELECT sum(body1) as body, sum(mice1) as mice, sum(sety1) as sety from utkani where hrac1 in(select hrac1 from skupina where id=66) 
  UNION ALL
  SELECT sum(body2) as body, sum(mice2) as mice, sum(sety2) as sety from utkani where hrac2 in(select hrac1 from skupina where id=66) 
) t1

Answer 2

我认为您错过了向正在查询的虚拟表添加别名

SELECT SUM(body), SUM(mice), SUM(sety) FROM
(
  SELECT sum(body1) as body, sum(mice1) as mice, sum(sety1) as sety from utkani where hrac1 in(select hrac1 from skupina where id=66) 
  UNION ALL
  SELECT sum(body2) as body, sum(mice2) as mice, sum(sety2) as sety from utkani where hrac2 in(select hrac1 from skupina where id=66) 
) as temp