我下面的异步函数返回 Promise { 的原因是什么<pending>而不是返回正确的值？

Question

当我从下面的代码中console.log() paymentResults 和 pendingResults 时，我可以看到数据被正确记录。 但是，就在我尝试退还付款和待处理的最后一刻，我在后端看到结果为Promise { <pending> } 。 原因是什么，我该如何解决这个问题？

const query = await pool.query(q);

const payments = query.rows.filter(o => getCategory(o) === "payment");
const pending = query.rows.filter(o => getCategory(o) === "pending");
const inactive = query.rows.filter(o => getCategory(o) === "inactive");

const paymentsResults = payments.map(async order => {

    const A = ({
        date: getDate(order),
        item: await getItem(order),
        total: getTotal(order),
        purchaser: getPurchaser(order),
        email: getEmail(order),
        paymentMethod: getPaidUsing(order),
        status: getStatus(order)
    });
    return A;
});



const pendingResults = pending.map(async order => {

    const B = {
        date: getDate(order),
        item: await getItem(order),
        total: getTotal(order),
        purchaser: getPurchaser(order),
        email: getEmail(order),
        status: getStatus(order)
    };

    return B;
});


return {
    payments: paymentsResults,
    pending: pendingResults,
    inactive: inactive
};
};

Answer 1

const paymentsResults = await Promise.all(payments.map(async order => {
    const A = {
        date: getDate(order),
        item: await getItem(order),
        total: getTotal(order),
        purchaser: getPurchaser(order),
        email: getEmail(order),
        paymentMethod: getPaidUsing(order),
        status: getStatus(order)
    };

    return A;
}));


const pendingResults = await Promise.all(pending.map(async order => {
    const B = {
        date: getDate(order),
        item: await getItem(order),
        total: getTotal(order),
        purchaser: getPurchaser(order),
        email: getEmail(order),
        status: getStatus(order)
    };

    return B;
}));

• Promise 数组在使用前需要通过Promise.all解析。
• 异步函数总是返回承诺。