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匹配具有相同属性的节点之间的关系

[英]Match relationships between nodes with the same property

我有以下图表:

CREATE (a:Node)
CREATE (b:Node)
CREATE (c:Node)
CREATE (d:Node)

CREATE (a)-[:rel {referenceId: 1234, amount: 2}]->(b)
CREATE (b)-[:rel {referenceId: 1234, amount: 1}]->(c)
CREATE (b)-[:rel {referenceId: 1234, amount: 0.5}]->(d)

CREATE (a)-[:rel {referenceId: 4567, amount: 4}]->(b)
CREATE (b)-[:rel {referenceId: 4567, amount: 1}]->(c)
CREATE (b)-[:rel {referenceId: 4567, amount: 3}]->(d)

我正在寻找一种方法来计算从 a 发送到 b 和从 b 发送到 c/d 的金额之间的差异,具体取决于 referenceId 但不使用特定的 referenceId。

所以我正在寻找类似下面的半代码的东西:

MATCH (a)-[in:rel]->(b)-[out:rel]->(c) WHERE in.referenceId == out.referenceId RETURN SUM(in.amount)-SUM(out.amount)

有人知道我该怎么做吗?

也许你需要按照referenceId来做?

  MATCH (a)-[in:rel]->(b)-[out:rel]->(c)
     WHERE in.referenceId = out.referenceId
  RETURN in.referenceId as referenceId, 
         SUM(in.amount)-SUM(out.amount) as diff

结果:

referenceId diff
4567        4
1234        2.5

您也可以通过某种方式来查找非零差异:

MATCH (a)-[in:rel]->(b)-[out:rel]->(c)
  WHERE in.referenceId = out.referenceId
WITH in.referenceId as referenceId,
       SUM(in.amount)-SUM(out.amount) as diff
WHERE diff <> 0
RETURN referenceId, diff

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