删除满足一个条件的所有记录

Question

我有一张如下表：

ID	部分	是_否
EE_1	秒_21	是
EE_1	秒_23	N
EE_1	秒_22	N
EE_2	秒_21	N

我正在寻找一种方法来仅返回“Yes_no”列中没有“Y”的 ID。 所需的输出如下：

ID	部分	是_否
EE_2	秒_21	N

Answer 1

我认为这就是你想要的：

create table MyTable(
  ID varchar(10),
  section varchar(50),
  Yes_no varchar(1)
)
insert into MyTable values 
('EE_1','sec_21','Y'),
('EE_1','sec_23','N'),
('EE_1','sec_22','N'),
('EE_2','sec_21','N')

select *
from MyTable t1
where t1.Yes_no = 'N' and not exists
(select * from MyTable t2 where t2.ID = t1.ID and t2.Yes_no = 'Y')

DBFiddler： https ://dbfiddle.uk/ ? rdbms = sqlserver_2019 & fiddle = 0b24198e227588df323c579facd37153

Answer 2

窗口函数通常是这种事情最快的

SELECT
  t.ID,
  t.section,
  t.Yes_no
FROM (
    SELECT *,
      CountY = COUNT(CASE WHEN t.Yes_no = 'Y' THEN 1 END) OVER (PARTITION BY t.ID)
    FROM YourTable t
) t
WHERE CountY = 0;

数据库<>小提琴

Answer 3

Select * from table_X where ID not in (Select ID from table_X where Yes_no ='Y')

运行示例

Answer 4

select *
from Table t
where t.Yes_no = 'N' and not exists
(select * from Table b where b.ID = b.ID and b.Yes_no = 'Y')