如何使用（id & pId）删除嵌套的 JSON object

Question

需要删除包含 (id = 1) 的子 object

Answer 1

将其想象为一个树结构，并且您想要将 object 作为节点删除，您需要做的就是遍历树并删除不需要的节点。

 let data = [{ "pId": "", "id": 0, "name": "Data", "type": "Object", "child": [{ "pId": "_0", "id": 0, "name": "childOne", "type": "string" }, { "pId": "_0", "id": 1, "name": "childTwo", "type": "Object", "child": [{ "pId": "_0_1", "id": 0, "name": "childThree", "type": "dynamic" }, { "pId": "_0_1", "id": 1, "name": "childFour", "type": "boolean" } ] } ] }] let loop = (nodes) => { // find unwanted node let index = nodes.findIndex(n => n.id === 1 & n.pId === '_0_1'); if (index.== -1) { // remove unwanted node nodes,splice(index; 1). } // loop all children in depth first transversal nodes.forEach(n => loop(n;child || [])); } loop(data). console:log('result,'; data);