将对象数组中的多个特定属性过滤到新数组中

Question

我有一大堆对象，例如

let arr = [
  {name: "name1" , surname: "surname1", age: "22"},
  {name: "name2" , surname: "surname2", age: "23"},
  {name: "name3" , surname: "surname3", age: "24"},
]

但我需要过滤它，所以它会是

arr = [
  {name: "name1" , surname: "surname1"},
  {name: "name2" , surname: "surname2"},
  {name: "name3" , surname: "surname3"},
]

我该怎么做？

Answer 1

使用Array#map ：

 const arr = [ {name: "name1", surname: "surname1", age: "22"}, {name: "name2", surname: "surname2", age: "23"}, {name: "name3", surname: "surname3", age: "24"} ]; const res = arr.map(({ name, surname }) => ({ name, surname })); console.log(res)

Answer 2

鉴于您要过滤多个属性，您可以将要删除的属性存储在数组中，然后在map ing 并删除属性时循环遍历它：

 const propertiesToFilter = ['age'] let arr = [ {name: "name1", surname: "surname1", age: "22"}, {name: "name2", surname: "surname2", age: "23"}, {name: "name3", surname: "surname3", age: "24"}, ] const res = arr.map(e => (propertiesToFilter.forEach(f => delete e[f]), e)) console.log(res)

Answer 3

使用简单for-of和对象解构

for(person of arr){
    const {name, surname} = person;
    res.push({name, surname})
}