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[英]sequelize - Specifying attributes for SELECT queries while using inner join
[英]Select and join with sequelize
如何用续集制作这段代码?
我使用了包含,但它带来了所有用户数据,但我只需要名称
select comments.comment, users.name from comments inner join users on comments.userId = users.id
我的代码:
Comments.findAll({
where: {
projectId: id
},
include: User
}).then(response =>{
res.json({comments: response})
})
如果您只想减少User
model 属性,则只需在attributes
选项中指明所需的属性:
Comments.findAll({
where: {
projectId: id
},
include: [{
model: User,
attributes: ['name']
}]
}).then(response =>{
res.json({comments: response})
})
如果您想将用户名添加为与所有Comments
字段相同级别的字符串属性,只需在Comments
model 的attributes
选项中使用所需的别名进行指示:
Comments.findAll({
where: {
projectId: id
},
attributes: [[Sequelize.col('Users.name'), 'userName']],
include: [{
model: User,
attributes: []
}]
}).then(response =>{
res.json({comments: response})
})
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