[英]Calculating totals and percentages for each row, in a time boxed window, for a relation
好的,所以我有两个表:作业和作业运行。 我正在使用 Postgres。
我想看2个时期。 7天前到现在,14天前到7天前。
对于每个作业,我想要总运行次数,以及每个时期成功和不成功运行的百分比。 我编造了这个可怕的查询:
WITH results AS (
select
coalesce(count(case when succeeded = true AND timestamp BETWEEN NOW() - INTERVAL '14 DAY' AND NOW() - INTERVAL '7 DAY' then 1 end), 0) as previous_passes,
coalesce(count(case when succeeded = false AND timestamp BETWEEN NOW() - INTERVAL '14 DAY' AND NOW() - INTERVAL '7 DAY' then 1 end), 0) as previous_failures,
coalesce(count(case when timestamp BETWEEN NOW() - INTERVAL '14 DAY' AND NOW() - INTERVAL '7 DAY' then 1 end), 0) as previous_total_runs,
coalesce(count(case when infrastructure_failure = true AND timestamp BETWEEN NOW() - INTERVAL '14 DAY' AND NOW() - INTERVAL '7 DAY' then 1 end), 0) as previous_infrastructure_failures,
coalesce(count(case when succeeded = true AND timestamp > NOW() - INTERVAL '7 DAY' then 1 end), 0) as current_passes,
coalesce(count(case when succeeded = false AND timestamp > NOW() - INTERVAL '7 DAY' then 1 end), 0) as current_failures,
coalesce(count(case when timestamp > NOW() - INTERVAL '7 DAY' then 1 end), 0) as current_total_runs,
coalesce(count(case when infrastructure_failure = true AND timestamp > NOW() - INTERVAL '7 DAY' then 1 end), 0) as current_infrastructure_failures
FROM
prow_job_runs JOIN prow_jobs ON prow_jobs.id = prow_job_runs.prow_job_id WHERE prow_jobs.name = 'promote-release-openshift-machine-os-content-e2e-aws-4.10'
)
SELECT *,
previous_passes * 100.0 / NULLIF(previous_total_runs, 0) AS previous_pass_percentage,
previous_failures * 100.0 / NULLIF(previous_total_runs, 0) AS previous_failure_percentage,
current_passes * 100.0 / NULLIF(current_total_runs, 0) AS current_pass_percentage,
current_failures * 100.0 / NULLIF(current_total_runs, 0) AS current_failure_percentage
FROM results;
这让我得到了我想要的结果:
-[ RECORD 1 ]--------------------+-----------------------
previous_passes | 591
previous_failures | 4
previous_total_runs | 595
previous_infrastructure_failures | 1
current_passes | 67
current_failures | 0
current_total_runs | 67
current_infrastructure_failures | 0
previous_pass_percentage | 99.3277310924369748
previous_failure_percentage | 0.67226890756302521008
current_pass_percentage | 100.0000000000000000
current_failure_percentage | 0.00000000000000000000
这是执行计划:
QUERY PLAN
------------------------------------------------------------------------------------------------------------------
Subquery Scan on results (cost=661.12..661.19 rows=1 width=192)
-> Aggregate (cost=661.12..661.13 rows=1 width=64)
-> Hash Join (cost=8.30..650.89 rows=93 width=10)
Hash Cond: (prow_job_runs.prow_job_id = prow_jobs.id)
-> Seq Scan on prow_job_runs (cost=0.00..603.60 rows=14460 width=18)
-> Hash (cost=8.29..8.29 rows=1 width=8)
-> Index Scan using prow_jobs_name_key on prow_jobs (cost=0.27..8.29 rows=1 width=8)
Index Cond: (name = 'promote-release-openshift-machine-os-content-e2e-aws-4.10'::text)
(8 rows)
但这仅适用于一项工作,如何在代码中不执行 for 循环的情况下获得每项工作的结果?
我还认为我的查询真的很慢,仅运行一项作业就需要 > 8 毫秒。
泰
您需要提供查询execution plan
。 但你必须确保你有必要的索引,也许你限制你的行数加入它会有所帮助:
WITH results AS (
select prow_jobs.name,
coalesce(count(case when succeeded = true AND timestamp BETWEEN NOW() - INTERVAL '14 DAY' AND NOW() - INTERVAL '7 DAY' then 1 end), 0) as previous_passes,
coalesce(count(case when succeeded = false AND timestamp BETWEEN NOW() - INTERVAL '14 DAY' AND NOW() - INTERVAL '7 DAY' then 1 end), 0) as previous_failures,
coalesce(count(case when timestamp BETWEEN NOW() - INTERVAL '14 DAY' AND NOW() - INTERVAL '7 DAY' then 1 end), 0) as previous_total_runs,
coalesce(count(case when infrastructure_failure = true AND timestamp BETWEEN NOW() - INTERVAL '14 DAY' AND NOW() - INTERVAL '7 DAY' then 1 end), 0) as previous_infrastructure_failures,
coalesce(count(case when succeeded = true AND timestamp > NOW() - INTERVAL '7 DAY' then 1 end), 0) as current_passes,
coalesce(count(case when succeeded = false AND timestamp > NOW() - INTERVAL '7 DAY' then 1 end), 0) as current_failures,
coalesce(count(case when timestamp > NOW() - INTERVAL '7 DAY' then 1 end), 0) as current_total_runs,
coalesce(count(case when infrastructure_failure = true AND timestamp > NOW() - INTERVAL '7 DAY' then 1 end), 0) as current_infrastructure_failures
FROM prow_job_runs
JOIN prow_jobs
ON prow_jobs.id = prow_job_runs.prow_job_id
and timestamp BETWEEN NOW() and now() - INTERVAL '14 DAY'
group by prow_jobs.name
)
SELECT *,
previous_passes * 100.0 / NULLIF(previous_total_runs, 0) AS previous_pass_percentage,
previous_failures * 100.0 / NULLIF(previous_total_runs, 0) AS previous_failure_percentage,
current_passes * 100.0 / NULLIF(current_total_runs, 0) AS current_pass_percentage,
current_failures * 100.0 / NULLIF(current_total_runs, 0) AS current_failure_percentage
FROM results;
并且似乎您在 prow_job_runs 表上没有任何索引,请在该表上添加一个包含列的索引(id、succeeded、infrastructure_failure、timestamp、prow_job_id)
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