[英]Finding part of string and extracting data between delimiter using BigQuery SQL
我有一个这样的专栏:
String_to_Extract |
---|
A~S1_B~S2_C~S11 |
A~S1_B~S3_C~S12 |
C~S13_A~S11_B~S4 |
“~”之前的部分应该是列名。 “~”后面的部分应该是行值。 这由“_”分隔。 因此,结果应如下所示:
String_to_Extract | 一个 | 乙 | C |
---|---|---|---|
A~S1_B~S2_C~S11 | S1 | S2 | S11 |
A~S1_B~S3_C~S12 | S1 | S3 | S12 |
C~S13_A~S11_B~S4 | S11 | S4 | S13 |
这是我的方法:
SELECT
String_to_Extract,
SUBSTRING(String_to_Extract, INSTR(Advertiser, "A~")+2, ?) AS A,
SUBSTRING(String_to_Extract, INSTR(Advertiser, "B~")+2, ?) AS B,
SUBSTRING(String_to_Extract, INSTR(Advertiser, "C~")+2, ?) AS C,
From Table
如何获得每列的 ~ 和下一个 _ 之间的部分?
很高兴得到帮助!
一种方法使用REGEXP_EXTRACT
:
SELECT
REGEXP_EXTRACT(String_to_Extract, r"(?:^|_)A~([^_]+)") AS A,
REGEXP_EXTRACT(String_to_Extract, r"(?:^|_)B~([^_]+)") AS B,
REGEXP_EXTRACT(String_to_Extract, r"(?:^|_)C~([^~]+)") AS C
FROM yourTable;
您也可以使用这种方法,首先订购拆分的项目,然后选择值:
select
split(ordered[safe_offset(0)], '~')[safe_offset(1)] as A,
split(ordered[safe_offset(1)], '~')[safe_offset(1)] as B,
split(ordered[safe_offset(2)], '~')[safe_offset(1)] as C
from (
select
array(select _ from unnest(split(Advertiser, '_') ) as _ order by 1) as ordered
from dataset.table
)
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