[英]String Type Vector C++
在我下面分享的代码中,我想在AddStoreCustomer()
部分中使用 output 向量数据类型。 这就是代码的工作方式。 但是代码中有一个错误。 如果我在客户变量中输入一个单词,代码就可以正常工作。 但是当我在这个变量中输入两个单词并且它们之间有一个空格时,代码不起作用。
#include <iostream>
#include <vector>
using namespace std;
class Store {
int StoreID;
string StoreName;
string StoreCity;
string StoreTown;
string StoreTel;
vector <string> StoreCustomer;
public:
Store(){}
Store(int sid, string sname, string scity, string stown, string stel, string scustomer) {
setStoreID(sid);
setStoreName(sname);
setStoreCity(scity);
setStoreTown(stown);
setStoreTel(stel);
setStoreCustomer(scustomer);
}
void setStoreID(int sid) {
StoreID = sid;
}
void setStoreName(string sname) {
StoreName = sname;
}
void setStoreCity(string scity) {
StoreCity = scity;
}
void setStoreTown(string stown) {
StoreTown = stown;
}
void setStoreTel(string stel) {
StoreTel = stel;
}
void setStoreCustomer(string scustomer) {
StoreCustomer.push_back(scustomer);
}
int getStoreID() {
return StoreID;
}
string getStoreName() {
return StoreName;
}
string getStoreCity() {
return StoreCity;
}
string getStoreTown() {
return StoreTown;
}
string getStoreTel() {
return StoreTel;
}
vector <string> getStoreCustomer() {
return StoreCustomer;
}
~Store(){}
};
Store s2[50];
void AddStore() {
int id, menu;
string name, city, town, tel;
for (int i = 0; i < 1; i++) {
cout << "Lutfen Magaza ID Numarasini Girin: ";
cin >> id;
s2[i].setStoreID(id);
cout << "Lutfen Magaza Adini Girin: ";
cin >> name;
s2[i].setStoreName(name);
cout << "Lutfen Magazanin Bulundugu Ili Girin: ";
cin >> city;
s2[i].setStoreCity(city);
cout << "Lutfen Magazanin Bulundugu Ilceyi Girin: ";
cin >> town;
s2[i].setStoreTown(town);
cout << "Lutfen Magazanin Telefon Numarasini Girin: ";
cin >> tel;
s2[i].setStoreTel(tel);
cout << "Magaza Eklendi" << endl;
cout << "\n\n";
}
cout << "Menuye Donmek icin 0 " << endl;
cin >> menu;
if (menu == 0) {
StoreMenu();
}
else {
cout << "Tanımlanamayan Giris!!!" << endl;
//Menu();
}
}
int Search2(const int& y) {
for (int j = 0; j < 100; j++) {
if (s2[j].getStoreID() == y)
return j;
}
return -1;
}
void AddStoreCustomer() {
int id, found, menu;
string customer;
cout << "Lutfen Musteri Eklemek Istediginiz Magazanin ID Numarasini Girin:";
cin >> id;
found = Search2(id);
if (found == -1)
{
cout << "Magaza Bulunamadi" << endl;
}
else {
cout << "Magaza Bulundu.\n" << "Lutfen Magaza Veri Tabanina Eklemek Istediginiz Musterinin Bilgilerini Girin: ";
cin >> customer;
s2[found].setStoreCustomer(customer);
cout << "Girilen Musteri Bilgisi Secilen Magazaya Eklendi";
cout << "Magaza ID: " << s2[found].getStoreID() << "\n Magaza Adi: " << s2[found].getStoreName() << "\n Magazanin Bulundugu Il: " << s2[found].getStoreCity() << "\n Magazanin Bulundugu Ilce:" << s2[found].getStoreTown() << "\n Magaza Iletisim Numarasi: " << s2[found].getStoreTel() << endl;
cout << "Musteriler: " << endl;
for (int i = 0; i < s2[found].getStoreCustomer().size(); i++)
{
cout << "\t\t" << s2[found].getStoreCustomer()[i] << endl;
}
}
cout << "Tekrar Giris Yapmak icin 1 Menuye Donmek icin 0 " << endl;
cin >> menu;
if (menu == 0) {
StoreMenu();
}
else if (menu == 1) {
AddStoreCustomer();
}
发生这种情况是因为您正在使用cin>>
读取输入,该输入一直读取到第一个空白符号。 如果您想阅读整行,请考虑使用std::getline()
代替:
getline(cin, customer);
谢谢您的帮助。 我修改了如下代码。 但是,当我运行代码时,它直接输出而不要求我输入。 我想知道我是否以错误的方式使用getline()
将其更新为getline(cin,customer)
而不是cin>> customer
void AddStoreCustomer() {
int id, found, menu;
string customer;
cout << "Lutfen Musteri Eklemek Istediginiz Magazanin ID Numarasini Girin:";
cin >> id;
found = Search2(id);
if (found == -1)
{
cout << "Magaza Bulunamadi" << endl;
}
else {
cout << "Magaza Bulundu.\n" << "Lutfen Magaza Veri Tabanina Eklemek Istediginiz Musterinin Bilgilerini Girin: ";
//cin >> customer;
getline(cin, customer);
s2[found].setStoreCustomer(customer);
cout << "Girilen Musteri Bilgisi Secilen Magazaya Eklendi";
cout << "Magaza ID: " << s2[found].getStoreID() << "\n Magaza Adi: " << s2[found].getStoreName() << "\n Magazanin Bulundugu Il: " << s2[found].getStoreCity() << "\n Magazanin Bulundugu Ilce:" << s2[found].getStoreTown() << "\n Magaza Iletisim Numarasi: " << s2[found].getStoreTel() << endl;
cout << "Musteriler: " << endl;
for (int i = 0; i < s2[found].getStoreCustomer().size(); i++)
{
cout << "\t\t" << s2[found].getStoreCustomer()[i] << endl;
}
}
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