谷歌应用脚本将所有数据从一个文件夹复制到另一个文件夹并防止脚本复制已经存在的文件

Question

我的 Google Drive 帐户中有两个文件夹； 假设文件夹 1 和文件夹 2。我会将文件夹 1 中的所有文件和文件夹复制到文件夹 2，但如果文件夹 2 中已经存在，则不应复制。 这是脚本，但是当它运行时，它总是将文件夹 1 中的所有可用数据复制到文件夹 2：

function copyTo() {
  var sourceFolder = "id1";
  var targetFolder = "id2";
  
  var source = DriveApp.getFolderById(sourceFolder);
  var target = DriveApp.getFolderById(targetFolder);
  copyFolder(source, target);
}

function copyFolder(source, target) {
  var folders = source.getFolders();
  var files = source.getFiles();
  
  while(files.hasNext()){
  var file = files.next();
  file.makeCopy(file.getName(), target);
  }
  
  while(folders.hasNext()){
    var subFolder = folders.next();
    var folderName = subFolder.getName();
    var targetFolder = target.createFolder(folderName);
    copyFolder(subFolder, targetFolder);
  }
}

Answer 1

您需要在目标文件夹中创建文件和文件夹列表，并根据列表检查要复制的文件的名称。

  function copyTo() {
    var sourceFolder = "id1";
    var targetFolder = "id2";


    var source = DriveApp.getFolderById(sourceFolder);
    var target = DriveApp.getFolderById(targetFolder);

    copyFolder(source, target);
  }

  function copyFolder(source, target) {
    var folderNames = existingFiles(target);
    var folders = source.getFolders();
    var files = source.getFiles();

    while (files.hasNext()) {
      var file = files.next();
      if (folderNames.files.indexOf(file.getName()) > -1) {
        file.makeCopy(file.getName(), target);
      }
    }

    while (folders.hasNext()) {
      var subFolder = folders.next();
      var folderName = subFolder.getName();
      if (folderNames.files.indexOf(folderName) > -1)
        var targetFolder = target.createFolder(folderName);
      copyFolder(subFolder, targetFolder);

    }
  }

  function existingFiles(folder) {
    var names = {
      files: [],
      folders: []
    };
    var folders = folder.getFolders();
    var files = folder.getFiles();

    while (files.hasNext()) {
      var file = files.next();
      names.files.push(file.getName());
    }

    while (folders.hasNext()) {
      var subFolder = folders.next();
      name.folder.push(subFolder.getName());
    }
    return names;
  }