Newtonsoft.JSON null 反序列化时的值

Question

我正在使用 .NET CORE 3.1 和 Newtonsoft.Json 反序列化来自 JSON 响应的 JSON 响应来自 ZADB97423887041

这是从 API 构造 JSON 响应的方式：

{
    "PageSize": 200,
    "PageCount": 1,
    "RecordCount": 13,
    "PageNumber": 1, 
    "Result": "OK",
    "organization":[ 
        {
            "5LevelOrganization": {
                "organizationLevel1Code": "xxxxxxxx",
                "organizationLevel1Name": "Corporate Human Resources",
                "organizationLevel2Code": "xxxxxxxx",
                "organizationLevel2Name": "BHR Downstream & Midstream",
                "organizationLevel3Code": "xxxxxxxx",
                "organizationLevel3Name": "Chemicals",
                "organizationLevel4Code": "",
                "organizationLevel4Name": "",
                "organizationLevel5Code": "xxxxxxxx",
                "organizationLevel5Name": "Chemicals"
            } 
        },
        { 
            "5LevelOrganization": { 
                "organizationLevel1Code": "xxxxxxxx",
                "organizationLevel1Name": "Corporate Human Resources", 
                "organizationLevel2Code": "xxxxxxxx",
                "organizationLevel2Name": "BHR Downstream & Midstream", 
                "organizationLevel3Code": "xxxxxxxx", 
                "organizationLevel3Name": "Chemicals", 
                "organizationLevel4Code": "xxxxxxxx", 
                "organizationLevel4Name": "Americas Oronite Manufacturing HR", 
                "organizationLevel5Code": "xxxxxxxx",
                "organizationLevel5Name": "Americas Oronite HR Managed" 
            }
        } 
    ] 
} 

这就是我关于响应构建 c# class 的方式：

public class _5LevelOrganization
    {
        [JsonPropertyName("organizationLevel1Code")]
        public string OrganizationLevel1Code { get; set; }

        [JsonPropertyName("organizationLevel1Name")]
        public string OrganizationLevel1Name { get; set; }

        [JsonPropertyName("organizationLevel2Code")]
        public string OrganizationLevel2Code { get; set; }

        [JsonPropertyName("organizationLevel2Name")]
        public string OrganizationLevel2Name { get; set; }

        [JsonPropertyName("organizationLevel3Code")]
        public string OrganizationLevel3Code { get; set; }

        [JsonPropertyName("organizationLevel3Name")]
        public string OrganizationLevel3Name { get; set; }

        [JsonPropertyName("organizationLevel4Code")]
        public string OrganizationLevel4Code { get; set; }

        [JsonPropertyName("organizationLevel4Name")]
        public string OrganizationLevel4Name { get; set; }

        [JsonPropertyName("organizationLevel5Code")]
        public string OrganizationLevel5Code { get; set; }

        [JsonPropertyName("organizationLevel5Name")]
        public string OrganizationLevel5Name { get; set; }
    }

    public class Organization
    {
        [JsonPropertyName("5LevelOrganization")]
        public _5LevelOrganization _5LevelOrganization { get; set; }
    }

    public class FiveLevel
    {
        [JsonPropertyName("PageSize")]
        public int PageSize { get; set; }

        [JsonPropertyName("PageCount")]
        public int PageCount { get; set; }

        [JsonPropertyName("RecordCount")]
        public int RecordCount { get; set; }

        [JsonPropertyName("PageNumber")]
        public int PageNumber { get; set; }

        [JsonPropertyName("Result")]
        public string Result { get; set; }

        [JsonPropertyName("organization")]
        public List<Organization> Organization { get; set; }
    }

问题是当我尝试反序列化响应 JSON 时，它总是导致 5LevelOrganization 的 null 值：

var fiveLevelResult = _5levelresponse.Content.ReadAsStringAsync().Result;
FiveLevel fivelevel = JsonConvert.DeserializeObject<FiveLevel>(fiveLevelResult);

NULL 5LevelOrganization 的图像

最初我认为问题出在 JSON 响应属性上，它以数字（5LevelOrganization）开头，所以我添加了 JsonPropertyAttribute 但它仍然无法正确反序列化，导致 NULL。 API 的响应与预期一致。

我只是想知道我哪里做错了？ 非常感谢任何帮助或信息。

Answer 1

正如 Llama 所说，当我从 JSON.NET 库切换[JsonPropertyName]到[JsonProperty]时，我使用的序列化程序的属性错误，结果与预期一致。

Answer 2

[JsonPropertyName] 是 System.Text.Json 属性，但您正在尝试使用 Newtonsoft.Json 解串器。

您必须将属性更改为 [JsonProperty] 或使用 System.Text.Json 反序列化器

using System.Text.Json;

FiveLevel fivelevel = JsonSerializer.Deserialize<FiveLevel>(fiveLevelResult);