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[英]HTML/PHP Storing values in table, saving to database and showing it later
[英]Storing JOIN Values in PHP and showing them as a table
我有以下 SQL 查询:
SELECT tbltasks.fldTaskNr
,tbltasks.fldRITMNr
,tbltasks.fldCHGNr
,tblci.fldCI
,tblgxp.fldGxP
,tblrequester.fldRequester
,tblstatus.fldStatus
,tbltasks.fldDescription
,tblresponsible.fldResponsible
,tbllocation.fldLocation
FROM tbltasks
LEFT JOIN tblCI ON tblci.pkCI = tbltasks.fkCI
LEFT JOIN tblgxp ON tblgxp.pkGxP = tbltasks.fkGxP
LEFT JOIN tblrequester ON tblrequester.pkRequester = tbltasks.fkRequester
LEFT JOIN tblstatus ON tblstatus.pkStatus = tbltasks.fkStatus
LEFT JOIN tblresponsible ON tblresponsible.pkResponsible = tbltasks.fkResponsible
LEFT JOIN tbllocation ON tbllocation.pkLocation = tbltasks.fkLocation
现在我想将这个查询的值和 output 存储为一个表,应该如下所示:
我得到下表为 HTML,output 应显示在此表中并重复自身,因为数据库中将有几个条目:
<th>Task Nr.</th>
<th>RITM Nr.</th>
<th>CHG Nr.</th>
<th>CI</th>
<th>GxP</th>
<th>Task Requester</th>
<th>Task Status</th>
<th>Description</th>
<th>Responsible</th>
<th style="width: 201px;">Location</th>
</tr>
我怎样才能做到这一点? 任何帮助表示赞赏!
这很容易,但过程有点长。 首先确保为您的查询列指定一个名称值,如下所示:
SELECT tbltasks.fldTaskNr AS "TASK_NR"
,tbltasks.fldRITMNr AS "RITMNR"
,tbltasks.fldCHGNr AS "CHGNR"
,tblci.fldCI AS "FLDCI"
,tblgxp.fldGxP AS "GXP"
,tblrequester.fldRequester AS "REQUESTER"
,tblstatus.fldStatus AS "FLD_STATUS"
,tbltasks.fldDescription AS "FLD_DESCRIPTION"
,tblresponsible.fldResponsible AS "RESPONSIBLE"
,tbllocation.fldLocation AS "LOCATION" FROM tbltasks .. (rest of your joints)
然后使用此代码将您的查询转换为 object 的数组
$data = array();
while ($row = mysqli_fetch_assoc($result)) {
$data[] = $row;
}
return $data;
完成此步骤后,我们可以继续您的 HTML 表部件
<tr>
<th>Task Nr.</th>
<th>RITM Nr.</th>
<th>CHG Nr.</th>
<th>CI</th>
<th>GxP</th>
<th>Task Requester</th>
<th>Task Status</th>
<th>Description</th>
<th>Responsible</th>
<th style="width: 201px;">Location</th>
</tr>
<?php
for($i = 0 ;$i < count($data); $i++){
echo '<tr>';
echo '<td>'.$data['TASK_NR'].'</td>';
echo '<td>'.$data['RITMNR'].'</td>';
echo '<td>'.$data['CHGNR'].'</td>';
echo '<td>'.$data['FLDCI'].'</td>';
echo '<td>'.$data['GXP'].'</td>';
echo '<td>'.$data['REQUESTER'].'</td>';
echo '<td>'.$data['FLD_STATUS'].'</td>';
echo '<td>'.$data['FLD_DESSCRIPTION'].'</td>';
echo '<td>'.$data['RESPONSIBLE'].'</td>';
echo '<td style="width: 201px;">'.$data['LOCATION'].'</td>';
echo '</tr>';
}
?>
希望这能解决您的问题,并确保您的文件扩展名是“.php”
如果发现有用,请投票给我的答案。 谢谢。
您可以使用 foarch 打印您拉入 html 的数据。
foreach ($data as $key => $val) {
<tr>
<td>
<?php echo $val ?>
</td>
</tr>
}
将上面的代码应用到自己的表和数据上,就可以得到你想要的结果。
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