[英]How to count the number of grouped rows in mysql when I already count the total rows
[英]COUNT() returns the total number of rows in the grouped table
我有两张桌子:
工作表:
[![在此处输入图像描述][1]][1]
FailedReason 表通过以下方式引用到 Job 表:
[![在此处输入图像描述][2]][2]
我的目标是根据故障原因计算故障率。
我的期望是得到一个结果,第一列包含failure reason name
,第二列包含所有total number of failed jobs
的total number of all jobs
(“成功”+“失败”),第三列包含由原因,第四列包含使用以下公式计算的failure ratio
:失败计数(3 列)/总计数(2 列)* 100。
我的 sql 查询:
SELECT
FailedReason.main_reason as "Failure reason",
COUNT(job.name) AS "Total jobs",
SUM(CASE WHEN job.status='failed' THEN 1 ELSE 0 END) AS "Total failed jobs",
SUM(CASE WHEN job.status='failed' THEN 1 ELSE 0 END) / COUNT(job.name) * 100 AS "Failure ratio"
FROM job
LEFT JOIN FailedReason
ON job.id=FailedReason.job_id
GROUP BY 1
ORDER BY 3 DESC
我得到的结果是计算聚合表中的作业总数。 结果,失败率是百分之一百。
[![在此处输入图像描述][3]][3]
我应该修改什么以获得正确的作业数量(“成功”+“失败”)并计算正确的比率值
样本数据:
CREATE TABLE failedreason (id INT PRIMARY KEY AUTO_INCREMENT,
job_id INT REFERENCES job(id),
main_reason varchar(255)
);
INSERT INTO failedreason (job_id, main_reason) VALUES (13095427, 'test case failure'),
(13095407, 'test case failure'),
(13095533, 'connection error'),
(13095546, 'connection error'),
(13098367, 'runner connection error'),
(13101522, 'script error');
CREATE TABLE job (id INT PRIMARY KEY,
created_at date,
finished_at date,
status varchar(255)
);
INSERT INTO job (id,
created_at ,
finished_at ,
status
)
VALUES (13095427, '2021-05-03 02:50:41', '2021-05-03 03:47:27', 'failed'),
(13095407, '2021-05-03 02:50:39', '2021-05-03 03:46:41', 'failed'),
(13095533, '2021-05-03 02:50:41', '2021-05-03 03:47:27', 'failed'),
(13095546, '2021-05-03 02:50:41', '2021-05-03 03:47:27', 'failed'),
(13098367, '2021-05-03 02:50:41', '2021-05-03 03:47:27', 'failed'),
(13101522, '2021-05-03 02:50:41', '2021-05-03 03:47:27', 'failed');
(13101444, '2021-05-03 02:50:41', '2021-05-03 03:47:27', 'success');
(13101445, '2021-05-03 02:50:41', '2021-05-03 03:47:27', 'success');
(13101446, '2021-05-03 02:50:41', '2021-05-03 03:47:27', 'success');
[1]: https://i.stack.imgur.com/CYnPg.png
[2]: https://i.stack.imgur.com/t3baS.png
[3]: https://i.stack.imgur.com/LC7Hp.png
计算唯一的作业,而不是链接的失败原因
SELECT
FailedReason.main_reason as "Failure reason",
COUNT(DISTINCT job.id) AS "Total jobs",
COUNT(DISTINCT CASE WHEN job.status='failed' THEN job.id END) AS "Total failed jobs",
COUNT(DISTINCT CASE WHEN job.status='failed' THEN job.id END) / COUNT(DISTINCT job.id) * 100 AS "Failure ratio"
FROM job
LEFT JOIN FailedReason
ON job.id = FailedReason.job_id
GROUP BY FailedReason.main_reason
ORDER BY 3 DESC
测试以下查询
SELECT
FailedReason.main_reason as "Failure reason",
SUM(CASE WHEN job.status='success' THEN 1 ELSE 0 END) + SUM(CASE WHEN job.status='failed' THEN 1 ELSE 0 END) AS "Total jobs",
SUM(CASE WHEN job.status='failed' THEN 1 ELSE 0 END) AS "Total failed jobs",
SUM(CASE WHEN job.status='failed' THEN 1 ELSE 0 END) / COUNT(job.name) * 100 AS "Failure ratio"
FROM job
LEFT JOIN FailedReason
ON job.id=FailedReason.job_id
GROUP BY 1
ORDER BY 3 DESC
您的查询未给出正确的总数,因此 % 不正确。
请试试这个
select reason, alltotal, failed,
failedtotal,
cast( (100.00 * failed /failedtotal) as numeric(10,2)) failedRatio ,
cast( (100.00 * failed /alltotal) as numeric(10,2)) failedPercent from
(SELECT
FailedReason.[main_reason] reason,
MAX(tots.total_jobs) alltotal,
MAX(ftots.total_failed) failedtotal,
COUNT(DISTINCT CASE WHEN job.status='failed' THEN job.id END) failed
FROM job, FailedReason,
(SELECT COUNT(*) AS total_failed FROM FailedReason) ftots ,
(SELECT COUNT(*) AS total_jobs FROM job) tots
where job.id = FailedReason.job_id
GROUP BY FailedReason.[main_reason]) finaltable
共享样本查询数据的结果
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