如果 object 和数组值在 javascript 中匹配，如何获取 object 密钥

Question

我想知道如何比较 javascript 中的 object 值和数组值

如果array value和object value相同，那么如何返回

object key中的 object 键值

var result = obj.values(obj).includes(arr2) ? 
'status: active' : 'status: inactive'

var obj = {
  "active": 12,
  "inactive": 14
  "neutral": 16
}

var arr1=[12]
var arr2=[12, 14]
var arr3=[12, 16]

Expected Output

//for arr1
status: active
// for arr2
status: active
status: neutral
// for arr3
status: active
status: inactive

Answer 1

您应该检查数组是否包含 object 值，反之亦然：

const matches = (object, array) => {
  for (const [key, value] of Object.entries(object)) {
    if (array.includes(value))
      return [key, value];
  }
};

这应该有效。

Answer 2

您可以简单地遍历数组，然后尝试获取值与数组value匹配的Object.entries(obj)返回的[key, value]元组。 找到后，返回元组中的key ，即：

arr.map(v => Object.entries(obj).find(x => x[1] === v)[0]);

注意：如果您的数组可能包含 object 中不存在的值，则上面的代码将引发错误，因为.find()将返回 undefined。 如果是这种情况，您需要捕获使用无效值的情况（防御性设计）：

arr.map(v => {
  const foundTuple = Object.entries(obj).find(x => x[1] === v);
  return foundTuple ? foundTuple[0] : null;
});

请参阅下面的概念验证：

 const obj = { "active": 12, "inactive": 14, "neutral": 16 } const arr1 = [12]; const arr2 = [12, 14]; const arr3 = [12, 16]; const invalid_arr = [12, 999]; function getKeys(obj, arr) { return arr.map(v => { const foundTuple = Object.entries(obj).find(x => x[1] === v); return foundTuple? foundTuple[0]: null; }); } console.log(getKeys(obj, arr1)); console.log(getKeys(obj, arr2)); console.log(getKeys(obj, arr3)); console.log(getKeys(obj, invalid_arr));

Answer 3

另一种解决方案

 const obj = { "active": 12, "inactive": 14, "neutral": 16 } const arr1 = [12]; const arr2 = [12, 14]; const arr3 = [12, 16]; const getStatuses= (obj, arr) => arr.map(arrValue => { const [status] = Object.entries(obj).find(([objKey, objValue]) => objValue === arrValue)?? [null]; return { status }; }); console.log(getStatuses(obj, arr1)); console.log(getStatuses(obj, arr2)); console.log(getStatuses(obj, arr3));

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Answer 4

使用Object.keys()获取密钥，然后通过从原始 object 中获取值来过滤它们，并检查它是否包含在数组中：

 const getStatus = (obj, arr) => Object.keys(obj).filter(key => arr.includes(obj[key])) const obj = { "active": 12, "inactive": 14, "neutral": 16 } const arr1 = [12]; const arr2 = [12, 14]; const arr3 = [12, 16]; console.log(getStatus(obj, arr1)); console.log(getStatus(obj, arr2)); console.log(getStatus(obj, arr3));