将动态 object 序列化为 class 文件

Question

有没有办法将动态 object 序列化为 class 定义？

• 不使用这样的在线序列化工具

例如：

dynamic test = new System.Dynamic.ExpandoObject();
test.property1 = "test";
test.property2 = 123;

至

public class test
{
   string property1;
   int property2;
}

Answer 1

你可以像这样制作一个运行时代码生成器，尽管我不确定这是否是你想要做的？

public static string GenerateClass(string className, ExpandoObject eObj)
{
    var sb = new StringBuilder();
    sb.Append("public class ");
    sb.Append(className);
    sb.AppendLine();
    sb.Append("{");
    sb.AppendLine();

    foreach (var property in (IDictionary<String, Object>)eObj)
    {
        sb.Append("    ");
        sb.Append(property.Value.GetType());
        sb.Append(" ");
        sb.Append(property.Key);
        sb.Append(" ");
        sb.Append("{ get; set; }");
        sb.AppendLine();
    }

    sb.Append("}");
    sb.AppendLine();
    return sb.ToString();
}

传递您的 expando object 返回：

public class test
{
    System.String property1 { get; set; }
    System.Int32 property2 { get; set; }
}

用法：

static void Main(string[] args)
{
    dynamic test = new System.Dynamic.ExpandoObject();
    test.property1 = "test";
    test.property2 = 123;

    Console.WriteLine(GenerateClass("test", (ExpandoObject)test));
}

**编辑：对于嵌套类型，您可以这样做：**

public static string GenerateClass(string className, ExpandoObject eObj)
{
    var sb = new StringBuilder();
    sb.Append("public class ");
    sb.Append(className);
    sb.AppendLine();
    sb.Append("{");
    sb.AppendLine();

    foreach (var property in (IDictionary<String, Object>)eObj)
    {
        string typeName = property.Value.GetType().Name;

        if (property.Value is ExpandoObject nestedEObj)
        {
            typeName = property.Key;
            sb.AppendLine();
            foreach (string nestedClassLine in GenerateClass(property.Key, nestedEObj).Split(Environment.NewLine))
            {
                sb.Append("    ");
                sb.Append(nestedClassLine);
                sb.AppendLine();
            }
        }

        sb.Append("    ");
        sb.Append(typeName);
        sb.Append(" ");
        sb.Append(property.Key);
        sb.Append(" ");
        sb.Append("{ get; set; }");
        sb.AppendLine();
    }
    sb.Append("}");
    sb.AppendLine();
    return sb.ToString();
}

用法：

    static void Main(string[] args)
    {
        dynamic test = new System.Dynamic.ExpandoObject();
        test.property1 = "test";
        test.property2 = 123;

        dynamic nest = new System.Dynamic.ExpandoObject();
        nest.property1 = "testForNest";
        nest.property2 = 456;

        test.nest = nest;

        Console.WriteLine(GenerateClass("test", (ExpandoObject)test));
    }

产生：

public class test
{
    String property1 { get; set; }
    Int32 property2 { get; set; }

    public class nest
    {
        String property1 { get; set; }
        Int32 property2 { get; set; }
    }

    nest nest { get; set; }
}

Answer 2

好吧，这里有一些棘手的解决方案：你可以使用 JSON 序列化

using System;
using Newtonsoft.Json;

namespace XY
{
    class MainClass
    {
        public static void Main(string[] args)
        {
            dynamic x = new System.Dynamic.ExpandoObject();
            x.property1 = "sadsa";

            var xy = JsonConvert.DeserializeObject<Test>(JsonConvert.SerializeObject(x));

            Console.WriteLine(xy.property1);
            Console.ReadKey();
        }
    }

    public class Test
    {
        public string property1 { get; set; }
    }
}