[英]How to handle pop up windows Java Selenium?
例如, TjMaxx
当用户第一次导航时,弹出 window 出现,有时是 2,很难抓住并继续前进。 我试过try catch,但它不起作用,因为它打开了一些我看不到的windows。 如何捕获所有 windows 并为来宾用户解除它们?
try {
WebElement closeWindowPromo = driver.findElement(By.xpath
("//div[@class =\"bx-row bx-row-submit bx-row-submit-no bx-row-2uaILGf bx-element-1360650-2uaILGf\"]//button[@data-click = 'close']"));
WebDriverWait w = new WebDriverWait(driver, 5);
w.until(ExpectedConditions.visibilityOfElementLocated((By) closeWindowPromo));
System.out.println("Element is visible");
} catch (NoSuchElementException n) {
System.out.println("Element is invisible");
}
wait = new WebDriverWait(driver, 10);
不要单击关闭按钮,而是尝试单击带有文本的元素,因为我不希望免费送货导致elementToBeClickable()
的WebDriverWait并且您可以使用以下任一Locator Strategies :
选择器:
new WebDriverWait(driver, 20).until(ExpectedConditions.elementToBeClickable(By.cssSelector("div[class*='bx-row-submit-no'] > button.bx-button[data-click = 'close'][type='reset']"))).click();
xpath :
new WebDriverWait(driver, 20).until(ExpectedConditions.elementToBeClickable(By.xpath("//button[@class='bx-button' and @data-click = 'close'][@type='reset' and contains(., 'shipping')]"))).click();
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