繁体   English   中英

Laravel 8 个嵌套的 Model 关系

[英]Laravel 8 nested Model Relationships

在此处输入图像描述 这是我的第一个 Laravel 项目,请多多包涵。 我正在尝试显示父->子层次结构(非递归),类似于以下内容:

  • 第一类
  • - - 项目清单
  • ----------资源1
  • - - 项目清单
  • ----------资源2
  • 第 2 类
  • -----清单项目1
  • -----列出项目2....等

我无法理解如何编写查询以获取链接到子语句的资源,而不是顶级类别,基本上是与子语句相关的内部连接。 目前是这样显示的;

    {
        "id": 1,
        "name": "Category 1: Practising plumbing overview",
        "description": "<p>Category 1: Practising plumbing overview</p>",
        "created_at": "2022-01-06 15:48:49",
        "updated_at": "2022-01-06 15:48:49",
        "deleted_at": null,
        "plumbing_area_id": 1,
        "category_id": 1,
        "SubStatement": [
            {
                "id": 1,
                "title": "Plying narrative for Category 1",
                "description": "<p>Body of content.</p>",
                "theme_id": 1,
                "plumbing_area_id": 1
            },
            {
                "id": 2,
                "title": "Lay narrative for Category 1",
                "description": "<p>body description.</p>",
                "theme_id": 1,
                "plumbing_area_id": 1
            }
        ],
        "resources": []
    },
    {
        "id": 2,
        "name": "Category 2: AAV Practising plumbing introduction",
        "description": "<p><strong>Category 2:</strong> AAV Practising plumbing introduction</p>",
        "created_at": "2022-01-06 15:49:12",
        "updated_at": "2022-01-06 15:49:12",
        "deleted_at": null,
        "plumbing_area_id": 1,
        "category_id": 1,
        "SubStatement": [
            {
                "id": 3,
                "title": "Plying narrative for Category 2",
                "description": "<p>Body of content;</p>",
                "theme_id": 2,
                "plumbing_area_id": 1
            },
            {
                "id": 4,
                "title": "Lay narrative for Category 2",
                "description": "<p>Body of content</p>",
                "theme_id": 2,
                "plumbing_area_id": 1
            }
        ],
        "resources": []
    },
    {
        "id": 3,
        "name": "Category 3: AAV Practising plumbing design",
        "description": "<p><strong>Category 3: </strong>AAV Practising plumbing design</p>",
        "created_at": "2022-01-06 15:49:47",
        "updated_at": "2022-01-06 15:49:47",
        "deleted_at": null,
        "plumbing_area_id": 1,
        "category_id": 1,
        "SubStatement": [
            {
                "id": 5,
                "title": "Plying narrative for Category 3",
                "description": "<p>Body of content;</p>",
                "theme_id": 3,
                "plumbing_area_id": 1
            },
            {
                "id": 6,
                "title": "Lay narrative for Category 3",
                "description": “Blah blah</p>",
                "theme_id": 3,
                "plumbing_area_id": 1
            }
        ],
        "resources": []
    },
    {
        "id": 4,
        "name": "Category 4: another “category,
        "description": “Body</p>",
        "created_at": "2022-01-06 15:50:04",
        "updated_at": "2022-01-06 15:50:04",
        "deleted_at": null,
        "plumbing_area_id": 1,
        "category_id": 1,
        "SubStatement": [
            {
                "id": 7,
                "title": "Plying narrative for Category 4",
                "description": "<p>sdfsdfsdf;</p>",
                "theme_id": 4,
                "plumbing_area_id": 1
            },
            {
                "id": 8,
                "title": "Lay narrative for Category 4",
                "description": "<p> sdfsdfsdfsdf</p>",
                "theme_id": 4,
                "plumbing_area_id": 1
            }
        ],
        "resources": []
    },
   ]

我正在寻找类似下面的东西,请注意资源节点的位置:

[
  {
    "id": 1,
    "name": "Category 1: Practising plumbing overview",
    "description": "<p>Category 1: Practising plumbing overview</p>",
    "created_at": "2022-01-06 15:48:49",
    "updated_at": "2022-01-06 15:48:49",
    "deleted_at": null,
    "plumbing_area_id": 1,
    "category_id": 1,
    "SubStatement": [
      {
        "id": 1,
        "title": "Plying narrative for Category 1",
        "description": "<p>Body of content.</p>",
        "theme_id": 1,
        "plumbing_area_id": 1,
        "resources": [
          {
            "id": 1,
            "resource_title": "The name of the resource"
          }
        ]
      }
    ]
  }
]

//主题 Model

{
   return $this->hasMany(Statement::class, 'theme_id', 'id');
}
public function resources()
{
 return $this->belongsToMany(Resource::class);
}

//下面的Controller正在输出上面的JSON

{
 $output = Theme::where ( 'category_id', '=', $category_id )
                    ->with(['subStatement' =>
                        fn ($query) =>
                        $query->select('id','title','description','theme_id','therapy_area_id')

                    ])
                    ->with(['resources' =>
                        fn ($query) =>
                        $query->select('id','temporary_url')])
                    ->get();
}

// 我试图写这样的东西。 它引发了“完整性约束违规:字段列表中的 1052 列 'id' 不明确”错误

{
    return $this->hasOneThrough(Statement::class, Resource::class);
}

您的主要问题是您需要嵌套查询。

  • 我将首先根据您的模式将关系添加到您的模型中。

  • 然后,如果我了解您要正确实现的目标,我将为嵌套添加基本查询。

楷模

主题.php


public function subStatements()
{
    return $this->hasMany(Statement::class); // 1-N
}

public function statements()
{
    return $this->belongsToMany(Statement::class); // N-N
}

public function resources
{
    return $this->belongsToMany(Resource::class); // N-N
}

声明.php


public function theme()
{
    return $this->belongsTo(Theme::class); // 1-N
}

public function themes()
{
    return $this->belongsToMany(Theme::class); // N-N
}

public function resources
{
    return $this->belongsToMany(Resource::class); // N-N
}

资源.php


public function themes()
{
    return $this->belongsToMany(Theme::class); // N-N
}

public function statements()
{
    return $this->belongsToMany(Statement::class); // N-N
}

询问


$themes = Theme::query()
               ->where('category_id', $category_id)
               ->with([
                  'subStatements' => fn ($query) => $query->with('resources') 
               ])
               ->get();  

暂无
暂无

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM