[英]Need help in using LISTAGG or REGEXP_REPLACE with DISTINCT function
[英]Need help in using LISTAGG function with DISTINCT
Select ID,
LISTAGG(DISTINCT VIEW_NM, ',') WITHIN GROUP(ORDER BY CAST(VISIT_PAGE_NBR as INT))
AS No_Of_Views
FROM db_name.schema_name.tbl_name
WHERE FLG_COLUMN = '0'
AND SOURCE_CD NOT IN ('1','2','3','4')
AND DATE_CR = '2022-01-01'
GROUP BY ID;
我希望以 ASC 或 DESC 顺序显示 VIEW_NM 列值。 但是当我做一个 DISTINCT VIEW_NM 时,我得到 - 它不是一个有效的 ORDER BY 表达式。 需要帮助来解决这个问题。
另外,我不希望 VIEW_NM 列的值被复制。 请建议如何做到这一点..
使用 cte 过滤出每个 ID 的多个 VIEW_NM(选择具有最低 VIST_PAGE_NBR 的一个):
WITH cte AS (
SELECT ID, VIEW_NM, VISIT_PAGE_NBR::INT AS VISIT_PAGE_NBR
FROM db_name.schema_name.tbl_name
WHERE FLG_COLUMN = '0'
AND SOURCE_CD NOT IN ('1','2','3','4')
AND DATE_CR = '2022-01-01'
QUALIFY ROW_NUMBER() OVER(PARTITION BY ID,VIEW_NM ORDER BY VISIT_PAGE_NBR) = 1
)
SELECT ID,
LISTAGG(VIEW_VM, ',') WITHIN GROUP(ORDER BY VISIT_PAGE_NBR) AS No_Of_Views
FROM cte
GROUP BY ID;
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