在 x86 汇编中运行总程序

Question

我正在尝试在 x86 程序集中编写一个程序，该程序接受 integer 输入，直到输入 0，此时它打印输入的所有整数的总和，以及其中的最小值。 我以前在 MIPS 汇编中编写过相同的程序，但在 x86 版本中遇到错误，其中总和似乎没有在 add 命令中递增。 我怎样才能让它工作？ 我应该直接使用寄存器吗？ 我在 x86 中包含了 MIPS 程序和我的尝试，它还没有最小值部分。

MIPS 程序（可以使用 MARS 运行它： http://courses.missouristate.edu/kenvollmar/mars/ ）：

#Sum and minimum finder; enter 0 to exit
.data
prompt: .asciiz "Input any integer: "
reply1: .asciiz "The sum of all the integers is "
reply2: .asciiz "The minimum value among the integers is "
period: .asciiz "."
newline: .asciiz "\n"

.text
#Register Usage:
# $t0 = current integer input from user
# $t1 = input sum
# $t2 = lowest value so far
# $t3 = minimum value checker bit
# $t4 = loop counter

#Get integer inputs
li $t0 1            #"Initialize" $t0 to 1 to avoid exiting the loop straight away
                
li $t4 0            #Set the loop counter to 0
loop1:              #Begin loop1
beqz $t0 exit1      #Exit loop if integer input is equal to zero

li $v0 4            #Print prompt1
la $a0 prompt
syscall

li $v0 5            #Take user input for prompt
syscall
move $t0 $v0        #Move user input from $v0 to $t0

add $t1 $t0 $t1     #Add integer to input sum
                
bgt $t4 $zero exit4 #For the first input only, set $t2 to $t0 without any comparisons
add $t2 $t0 $zero
exit4:
ble $t4 $zero exit3 #For all other subsequent inputs, compare the input in $t0 to the current min value in $t2
beqz $t0 exit2      #Do not do this if $t0 is equal to 0
slt $t3 $t2 $t0     #Implement low water mark algorithm, and check if $t2 < $t0
beq $t3 1 statusquo #If $t2 < $t0, then go to statusquo
add $t2 $t0 $zero   #If $t0 is less than the current value in $t2, then the status quo is not kept, and the value in $t2 is replaced by the one in $t0
statusquo:
exit2:
exit3:

addi $t4 $t4 1      #Increment first loop counter by one
j loop1             #Repeat loop1
exit1:              #Exit loop1

#Print blank space
li $v0 4            #Place a gap between the input and the output
la $a0 newline
syscall

#Print integer input sum
li $v0 4            #Print reply context
la $a0 reply1
syscall
li $v0 1            #Print sum
move $a0 $t1
syscall
li $v0 4            #Print period to end sentence
la $a0 period
syscall

#Print blank space
li $v0 4            #Place a newline here
la $a0 newline
syscall

#Print minimum value
li $v0 4            #Print reply context
la $a0 reply2
syscall
li $v0 1            #Print min value
move $a0 $t2
syscall
li $v0 4            #Print period to end sentence
la $a0 period
syscall

x86 尝试（使用尔湾图书馆： https://asmirvine.com/ ）：

;This program outputs the sum and minimum of the integers entered, enter 0 to quit.

include \irvine\irvine32.inc
includelib \irvine\irvine32.lib

.data
prompt byte "Input any integer: ",0
space byte " ",0
reply1 byte "The sum of all the integers entered is ",0
reply2 byte "The minimum value among the integers entered is ",0
period byte ".",0
newline byte "\n",0 ;?
num dword ?
sum dword ?
min dword ?
minflag dword ?
loopinc dword ?

.code
main proc

mov num, 1 ;initialize num to 1 to avoid exiting the loop right away

mov loopinc, 0
loop1:
test eax, eax
je exit1

mov edx, offset prompt ;print prompt to console
call writestring

call readint ;take num input
mov num, eax ;move input to num variable
add sum, eax ;add input to sum

add loopinc, 1
loop loop1
exit1:

call crlf ;insert newline

mov edx, offset reply1 ;print reply
call writestring

mov edx, sum ;print sum
call writedec

mov edx, offset period ;print period
call writestring

exit

main endp
end main

Answer 1

您错误地使用WriteDec 。 它需要EAX中的输入参数，而不是EDX中的。

参见文档： https://csc.csudh.edu/mmccullough/asm/help/source/irvinelib/writedec.htm