[英]Select statement for trial balance display from table with only one amount column and debit credit column
我正在尝试使用来自 MySQL/MariaDB 的 SQL 查询来填充 data.table,以将其显示为报告的试算表。
我的数据库引擎是MariaDB 10.4.19
对于这个例子.. 我有 2 个表。
| id | date | debit | credit| amount |
|----|------------|-------|-------|-----------|
| 1 | 2021-09-01 | 8 | 2 | 5000.000 |
| 6 | 2021-09-22 | 22 | 17 | 4750.000 |
| 8 | 2021-09-05 | 8 | 3 | 1485.000 |
| 9 | 2021-08-10 | 8 | 6 | 108.000 |
| 10 | 2021-07-07 | 8 | 23 | 98756.000 |
| id | name | desc | status |
|----|-----------------------------------|-----------------------------------|--------|
| 1 | Assets | Current Assets | 1 |
| 2 | Stockholders equity | Stockholders or Owners equity | 1 |
| 3 | Liability | Liabilities related accounts | 1 |
| 4 | Operating Revenues | Operating Revenues | 1 |
| 5 | Operating Expenses | Operating Expenses | 1 |
| 6 | Non-operating revenues and gains | Non-operating revenues and gains | 1 |
| 7 | Non-operating expenses and losses | Non-operating expenses and losses | 1 |
| 8 | Cash | For cash transaction | 1 |
现在从我的程序中,如果我 select 一个帐户(从分类帐中填充)并提交它将发送它的 ID。 使用该帐户 ID,我已经根据该帐户 ID 填充了所有交易。
例如:如果我选择现金账户,它会发送让我们说它会发送 8 作为 id。
现在
如以上几点,从程序中,如果帐户 ID 作为 8(即“现金”)传递,则SQL SELECT查询结果的期望输出应如下所示...
| Date | Account | Debit | Credit |
|------------|----------------------------------|---------:|----------:|
| 2021-09-01 | Stockholders equity | 0.00 | 5000.00 |
| 2021-09-05 | Liability | 0.00 | 1485.00 |
| 2021-08-10 | Non-operating revenues and gains | 0.00 | 108.00 |
| 2021-07-07 | Land | 0.00 | 98756.00 |
| 2021-02-25 | Land | 21564.00 | 0.00 |
| 2021-01-19 | Vehicles | 0.00 | 23132.00 |
| 2020-05-19 | Buildings Asset | 465.00 | 0.00 |
| 2019-09-01 | Non-operating revenues and gains | 315.00 | 0.00 |
| 2019-05-23 | Land | 346.00 | 0.00 |
| 2018-04-12 | Cash | 0.00 | 697.00 |
| 2017-05-15 | Non-operating revenues and gains | 0.00 | 999.00 |
| 2018-06-18 | Operating Revenues | 0.00 | 496.00 |
| 2018-06-23 | Liability | 0.00 | 426.00 |
| 2019-12-12 | Assets | 0.00 | 1684.00 |
| 2018-07-15 | Land | 0.00 | 1649.00 |
| 2018-07-22 | Land | 3666.00 | 0.00 |
| 2018-05-14 | Non-operating revenues and gains | 0.00 | 489.00 |
| 2018-09-16 | Equipment | 692.00 | 0.00 |
| 2021-04-18 | Non-operating revenues and gains | 4986.00 | 0.00 |
| 2020-04-19 | Land | 4956.00 | 0.00 |
| 2019-03-15 | Buildings Asset | 0.00 | 4988.00 |
| 2019-12-04 | Inventory | 0.00 | 7946.00 |
| 2019-08-25 | Stockholders equity | 0.00 | 19449.00 |
| | | | |
| | Total | 36990.00 | 167304.00 |
| | Balance | | 130314.00 |
这是 SQLFiddle http://sqlfiddle.com/#!9/fe2a00/2中的示例数据
你能给我一个关于如何使用连接和/或联合使用 SQL 查询填充此结果表的想法,还是我应该使用其他方式......
请帮忙解答!
没有Total
:
SELECT journal.date `Date`,
ledger.name Account,
CASE WHEN journal.dracc = 8
THEN 0.000
ELSE amount
END Debit,
CASE WHEN journal.dracc = 8
THEN amount
ELSE 0.000
END Credit
FROM journal
JOIN ledger ON (ledger.id, 8) IN ((dracc, cracc), (cracc, dracc));
Total
:
SELECT CASE WHEN NOT GROUPING(journal.id)
THEN MAX(journal.date)
END `Date`,
CASE WHEN NOT GROUPING(journal.id)
THEN MAX(ledger.name)
ELSE 'Total'
END Account,
SUM(CASE WHEN journal.dracc = 8
THEN 0
ELSE amount
END) Debit,
SUM(CASE WHEN journal.dracc = 8
THEN amount
ELSE 0
END) Credit
FROM journal
JOIN ledger ON (ledger.id, 8) IN ((dracc, cracc), (cracc, dracc))
GROUP BY journal.id WITH ROLLUP;
Total
和Balance
:
WITH
cte AS (
SELECT CASE WHEN NOT GROUPING(journal.id)
THEN MAX(journal.date)
END `Date`,
CASE WHEN NOT GROUPING(journal.id)
THEN MAX(ledger.name)
ELSE 'Total'
END Account,
SUM(CASE WHEN journal.dracc = 8
THEN 0
ELSE amount
END) Debit,
SUM(CASE WHEN journal.dracc = 8
THEN amount
ELSE 0
END) Credit
FROM journal
JOIN ledger ON (ledger.id, 8) IN ((dracc, cracc), (cracc, dracc))
GROUP BY journal.id WITH ROLLUP
)
SELECT *
FROM cte
UNION ALL
SELECT NULL, 'Balance', NULL, Credit - Debit
FROM cte
WHERE `Date` IS NULL;
https://dbfiddle.uk/?rdbms=mysql_8.0&fiddle=794f87b054848b1584a6c8dd2dd5d47c
如果您的 MySQL 版本是 5.x 那么:
WHEN NOT GROUPING(journal.id)
替换为WHEN journal.id IS NOT NULL
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