MSP430FR2476 中的 12 位 ADC 似乎只能在 10 位模式下工作

Question

问题是：我正在尝试初始化 MSP430FR2476 上的 12 位内置 ADC，但无论我做什么，它似乎都以 10 位工作。 我更改了控制寄存器中的分辨率位，唉，没有用。 无论我尝试了什么，都没有任何帮助，总是 10 位。 最高有效字节永远不会高于 3。请帮助，这是代码片段：

 //Configuring ADC

  PMMCTL2 |= (INTREFEN);            //Internal reference, default 1.5V
  ADCCTL0=ADCCTL1 = 0;              //Ensuring that the ADC is off
  ADCCTL0 |= (ADCSHT_7 + ADCMSC);   //sample and hold = 64clk, multiple conversion
  ADCCTL1 |= (ADCSHP + ADCSSEL_2 + ADCCONSEQ_1 + ADCDIV_7);        //Conversion is triggered 
                                   //manually, ADC clock source - SMCLK/8 ~ 2Mhz, sequence of 
                                             //channels single conversion,
  ADCCTL2 |= (ADCRES_2);         //12 bit resolution, no matter what setting I have, no change
  ADCMCTL0 |= (ADCSREF_1 + ADCINCH_1);       //Employing the internal reference and starting 
                                             //conversion from A1 (P1.1)
  ADCIE |= ADCIE0;                           //Activate interrupt
  ADCCTL0 |= (ADCON);                        //Switching ADC on
  SYSCFG2 |= (BIT1);                         //Activate ADC module on the pins (this line 
                                             //doesn't do anything for some reason

void adc_convert_begin(){
    ADCCTL0 |= ADCENC;
    ADCCTL0 |= ADCSC;           //Start conversion
      

//The interrupt simpy send the most significant byte over UART
__attribute__((interrupt(ADC_VECTOR)))
void ADC_ISR(void){
    switch(__even_in_range (ADCIV, 0x0C)){
    case 0x0C:
        adc_data[adc_index] = ADCMEM0;
        UCA1TXBUF = (unsigned char)(ADCMEM0>>8);
        break;
    }
}

Answer 1

错误恰好在这里：

ADCCTL2 |= (ADCRES_2); 

我的想法是默认值为 1，所以当我对寄存器执行|=操作时，最终值变成 3，而不是 2。我需要先将该位域清零！