[英]Flip a Multiple Columns and multiple rows in table in Snowflake
无法 pivot 雪花中的多列,如果有人能帮助我,我将不胜感激:
我基本上在左侧的屏幕截图中附加了表格,需要将其更改为右侧的格式。 我想知道 pivot 在这种情况下是否可以工作?
我当前的代码:
select
CONCAT(RIGHT(TO_VARCHAR(YEAR(DATE)),2),'-Q',TO_VARCHAR(QUARTER(DATE)) ) closed_date,
IFNULL(sum(case when STAG='Closed' then REVENUE_AMOUNTS end),0) REVENUE AMER,
IFNULL(sum(case when STAG='Closed' then REVENUE_AMOUNTS end),0) REVENUE APAC,
IFNULL(sum(case when STAG='Closed' then REVENUE_AMOUNTS end),0) REVENUE EMEA
from REVENUE_TABLE
where 1=1
group by 1
order by 1 asc
因此,假设您发布的 SQL 更像是这样(在 CTE 中包含虚假数据)
WITH REVENUE_TABLE as (
SELECT * FROM VALUES
('Closed', 1, '2020-01-01'::date, 'amer'),
('Closed', 2, '2020-04-01'::date, 'apac'),
('Closed', 3, '2020-08-01'::date, 'emea'),
('Closed', 4, '2021-01-01'::date, 'emea')
v(stag, REVENUE_AMOUNTS, date, loc)
)
select
CONCAT(RIGHT(TO_VARCHAR(YEAR(DATE)),2),'-Q',TO_VARCHAR(QUARTER(DATE)) ) closed_date,
ZEROIFNULL(sum(IFF(loc='amer' AND STAG='Closed', REVENUE_AMOUNTS, null))) as REVENUE_AMER,
ZEROIFNULL(sum(IFF(loc='apac' AND STAG='Closed', REVENUE_AMOUNTS, null))) as REVENUE_APAC,
ZEROIFNULL(sum(IFF(loc='emea' AND STAG='Closed', REVENUE_AMOUNTS, null))) as REVENUE_EMEA
from REVENUE_TABLE
group by 1
order by 1 asc
我将您的CASE
换成IFF
,并将它属于哪一列。我将IFNULL(x, 0)
ZEROIFNULL(x)
,时间更长,意图更清晰。
它给出的结果看起来像您现有的 output:
CLOSED_DATE | REVENUE_AMER | 收入_亚太地区 | 收入_欧洲、中东和非洲 |
---|---|---|---|
20-Q1 | 1个 | 0 | 0 |
20-Q2 | 0 | 2个 | 0 |
20-Q3 | 0 | 0 | 3个 |
21-Q1 | 0 | 0 | 4个 |
因此,如果它保持“原样”,那么要到达“你想去的地方”,你需要找到一组不同的值或位置,然后根据它加入你的结果。
select l.loc,
ZEROIFNULL(sum(IFF(r.cd='20-Q1', r.REVENUE_AMOUNTS, null))) as "20-Q1",
ZEROIFNULL(sum(IFF(r.cd='20-Q2', r.REVENUE_AMOUNTS, null))) as "20-Q2",
ZEROIFNULL(sum(IFF(r.cd='20-Q3', r.REVENUE_AMOUNTS, null))) as "20-Q3",
ZEROIFNULL(sum(IFF(r.cd='21-Q1', r.REVENUE_AMOUNTS, null))) as "21-Q1"
from (
select distinct loc
FROM REVENUE_TABLE
) as l
left join (
select loc,
revenue_amounts,
CONCAT(RIGHT(TO_VARCHAR(YEAR(DATE)),2),'-Q',TO_VARCHAR(QUARTER(DATE)) ) cd
FROM REVENUE_TABLE
WHERE STAG='Closed'
) as r on l.loc = r.loc
group by 1
order by 1 asc;
给出:
本地代码 | 20-Q1 | 20-Q2 | 20-Q3 | 21-Q1 |
---|---|---|---|---|
阿米尔 | 1个 | 0 | 0 | 0 |
亚太地区 | 0 | 2个 | 0 | 0 |
欧洲、中东和非洲 | 0 | 0 | 3个 | 4个 |
现在这种模式的缺点是您需要明确知道列名,但在 PIVOT 的情况下也有这个问题。 我相信这可以通过 Snowflake Scripting 来解决。
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