如何按某些属性值对对象数组进行分组

Question

我有两个 arrays。 一个包含名称的字符串数组

let companies = ['Google', 'Coca Cola,' 'Jonson & Jonson',];

另一个数组包含有人的对象

let employees = [
  {name: 'Alina' company: 'Google', id : 1},
  {name: 'Vika' company: 'Coca Cola', id : 2},
  {name: 'Alex' company: 'Jonson & Jonson', id : 3},
  {name: 'Vlad' company: 'Google', id : 4},
  {name: 'Fibi' company: 'Coca Cola', id : 5},
  {name: 'Joey' company: 'Google', id : 6},
]

我的任务是按名字对这些人进行分组

const groups = [
 {'Google': [
   {name: 'Alina' company: 'Google', id : 1},
   {name: 'Vlad' company: 'Google', id : 4},
 ]},
 'Jonson & Jonso': [
   {name: 'Alex' company: 'Jonson & Jonson', id : 3},
 ]},
 ...
]

也许任何人都知道如何以最简单的方式做到这一点，而无需对 JS 进行额外的迭代？ 我可以使用嵌套循环，但这太复杂了。 也许有可能与lodash ？ 另请注意，公司名称的字符串键可能包含空格。 将非常感谢任何建议。

Answer 1

回到未来的答案：

许多浏览器尚不支持，但很快就会出现（TC39 的第 3 阶段）并且已经在 polyfill core-js 中可用）是数组对象上的新groupBy方法。

这将允许您直接这样做：

employees.groupBy(employee => employee.company);

甚至 ：

employees.groupBy(({company}) => company);

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/groupBy

Answer 2

 let employees = [ {name: 'Alina', company: 'Google', id : 1}, {name: 'Vika', company: 'Coca Cola', id : 2}, {name: 'Alex', company: 'Jonson & Jonson', id : 3}, {name: 'Vlad', company: 'Google', id : 4}, {name: 'Fibi', company: 'Coca Cola', id : 5}, {name: 'Joey', company: 'Google', id : 6}, ] function groupBy(arr, property) { return arr.reduce(function (memo, x) { if (!memo[x[property]]) { memo[x[property]] = []; } memo[x[property]].push(x); return memo; }, {}); }; console.log(groupBy(employees,'company'));

Answer 3

最简单的方法是：

let employees = [
  {name: 'Alina' company: 'Google', id : 1},
  {name: 'Vika' company: 'Coca Cola', id : 2},
  {name: 'Alex' company: 'Jonson & Jonson', id : 3},
  {name: 'Vlad' company: 'Google', id : 4},
  {name: 'Fibi' company: 'Coca Cola', id : 5},
  {name: 'Joey' company: 'Google', id : 6},
]

const grouped = groupBy(employees, employee => employee.company);

Answer 4

伙计，如果你在提问之前甚至不检查你的结构是否没有错误，这似乎不尊重潜在的响应者。 非易失性：/

所以，有固定的变量：

let companies = ['Google', 'Coca Cola', 'Jonson & Jonson'];
let employees = [
  {name: 'Alina', company: 'Google', id : 1},
  {name: 'Vika', company: 'Coca Cola', id : 2},
  {name: 'Alex', company: 'Jonson & Jonson', id : 3},
  {name: 'Vlad', company: 'Google', id : 4},
  {name: 'Fibi', company: 'Coca Cola', id : 5},
  {name: 'Joey', company: 'Google', id : 6}]

请注意， companies是多余的，因为所有需要的信息都在employees中。

您正在寻找的结构可能是Map 。 你只需这样做：

let map = new Map()
employees.forEach((currentValue) => {
    map.has(currentValue.company) 
    ? map.get(currentValue.company).push({name: currentValue.name, id: currentValue.id})
    : map.set(currentValue.company, [{name: currentValue.name, id: currentValue.id}])
});

得到这个结果（在employee对象中不再需要现场company ）：

{
  Coca Cola: [{
  id: 2,
  name: "Vika"
}, {
  id: 5,
  name: "Fibi"
}],
  Google: [{
  id: 1,
  name: "Alina"
}, {
  id: 4,
  name: "Vlad"
}, {
  id: 6,
  name: "Joey"
}],
  Jonson & Jonson: [{
  id: 3,
  name: "Alex"
}]
}

Answer 5

因为你走的是简单的路线，所以会有点长。

let companies = ['Google', 'Coca Cola,' 'Jonson & Jonson',];

let employees = [
  {name: 'Alina' company: 'Google', id : 1},
  {name: 'Vika' company: 'Coca Cola', id : 2},
  {name: 'Alex' company: 'Jonson & Jonson', id : 3},
  {name: 'Vlad' company: 'Google', id : 4},
  {name: 'Fibi' company: 'Coca Cola', id : 5},
  {name: 'Joey' company: 'Google', id : 6},
]

//Let's create an intermediate object 
let interm = {};
/*This would create an object like 
 {
 Key:[],
 Key2:[],
 ...
 }

*/
companies.forEach((each)=>{
    interm[`${each}`] = [];
})

/*filling that interm a
Object with values like

{
'Google':[
{name: 'Alina' company: 'Google', id : 1}, 
{name: 'Vlad' company: 'Google', id : 4},
{name: 'Joey' company: 'Google', id : 6}
],
 Coca Cola:[
{name: 'Vika' company: 'Coca Cola', id : 2},
  {name: 'Fibi' company: 'Coca Cola', id : 5},
],
"Jonson & Jonson":[
 {name: 'Alex' company: 'Jonson & Jonson', id : 3},
]    
}

*/

employee.forEach((each)=>{
    if(companies.indexOf(each.company) != -1)
    interm[`${each.company}`].push(each)

})

//Now our intermediate data is ready 
//We need to convert to our   desirable format
let finalArray = []
Object.keys(interm).forEach((each)=>{
    finalArray.push({each:interm[`${each}`]})
})

console.log(finalArray)