[英]How to navigate to other screen from navigation drawer in flutter
我尝试了以下方法但它不起作用请告诉我解决方案
import 'package:book_recommendation_app/about.dart';
import 'package:book_recommendation_app/home.dart';
import 'package:flutter/material.dart';
import 'package:firebase_core/firebase_core.dart';
Future<void> main() async {
WidgetsFlutterBinding.ensureInitialized();
await Firebase.initializeApp();
runApp(const MyApp());
}
class MyApp extends StatelessWidget {
const MyApp({Key? key}) : super(key: key);
void onTap(menuItem) {
switch (menuItem) {
case 'item1':
print('item1 clicked');
break;
case 'item2':
print('item2 clicked');
break;
case 'item3':
print('item3 clicked');
break;
}
}
// This widget is the root of your application.
@override
Widget build(BuildContext context) {
var menuItems = <String>['item1', 'item2', 'item3'];
return MaterialApp(
title: 'Book Reccomendation Demo',
home: Scaffold(
appBar: AppBar(
title: Text('Home'),
actions: <Widget>[
PopupMenuButton<String>(
onSelected: onTap,
itemBuilder: (BuildContext context) {
return menuItems.map((String choice) {
return PopupMenuItem<String>(
child: Text(choice),
value: choice,
);
}).toList();
})
],
),
body: searchBar(),
drawer: Drawer(
child: ListView(
padding: EdgeInsets.zero,
children: [
const DrawerHeader(
decoration: BoxDecoration(
color: Colors.blue,
),
child: Text('Drawer Header'),
),
ListTile(
title: const Text('Item 1'),
onTap: () {
Navigator.pop(context);
},
),
ListTile(
title: const Text('About us'),
onTap: () {
Navigator.push(
context,
MaterialPageRoute(builder: (context) => AboutUs()),
);
Navigator.pop(context);
},
),
],
),
),
),
// home: const MyHomePage(title: 'Book Reccomendation Demo Home Page'),
);
}
}
// This widget is the root of your application.
@override
Widget build(BuildContext context) {
var menuItems = <String>['item1', 'item2', 'item3'];
return MaterialApp(
title: 'Book Reccomendation Demo',
home: Scaffold(
appBar: AppBar(
title: Text('Home'),
actions: <Widget>[
PopupMenuButton<String>(
onSelected: onTap,
itemBuilder: (BuildContext context) {
return menuItems.map((String choice) {
return PopupMenuItem<String>(
child: Text(choice),
value: choice,
);
}).toList();
})
],
),
body: searchBar(),
drawer: Drawer(
child: ListView(
padding: EdgeInsets.zero,
children: [
const DrawerHeader(
decoration: BoxDecoration(
color: Colors.blue,
),
child: Text('Drawer Header'),
),
ListTile(
title: const Text('Item 1'),
onTap: () {
Navigator.pop(context);
},
),
ListTile(
title: const Text('About us'),
onTap: () {
Navigator.push(
context,
MaterialPageRoute(builder: (context) => AboutUs()),
);
Navigator.pop(context);
},
),
],
),
),
),
// home: const MyHomePage(title: 'Book Reccomendation Demo Home Page'),
);
} }
不要在调用 Navigator.push 后立即调用 Navigator.pop(context)。 因为对我来说,它看起来像是你目前正在推送到下一个屏幕,但会立即再次弹出,这样就永远无法到达。
在这个 ListTile 中
ListTile(
title: const Text('About us'),
onTap: () {
Navigator.push(
context,
MaterialPageRoute(builder: (context) => AboutUs()),
);
Navigator.pop(context);
},
),
你使用Navigator.Push(context,MaterialPageRout(builder: (context) => AboutUs()));
然后你使用Navegator.pop(context);
这意味着你推一个新屏幕然后你关闭它,这就是问题所在
你只需要删除这一行Navigator.pop(context);
如果您不想使用MaterialPageRoute
go,您也可以使用GetX以更轻松的方式导航您的页面。
ListTile(
title: const Text('About us'),
onTap: () {
Get.to(AboutUs());
Navigator.pop(context);
},
),
在推到新屏幕之前弹出抽屉,喜欢
Navigator.pop(context);
Navigator.push(context,
MaterialPageRoute(builder: (context) => AboutUs(),
),
);
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