将数组值与特定键组合具有相同的值

Question

我有以下数组：

[
    {
       amendment: 1,
       lcnumber: "A1114564564CT",
       31D: "New Note"
    },
   {
      27: "0/0 (Number)(Total)",
      amendment: 1,
      lcnumber: "A1114564564CT",
   },
   {
      amendment: 2,
      lcnumber: "A1114564564CT",
      31D: "IN SINGAPORE (120 Days from L/C issue date)",
      32B: "USD"
   },
   {
     27: "2/2 (Number)(Total)",
     amendment: 2,
     lcnumber: "A1114564564CT",
     39B: "Exceeding"
   }
  ]

我想做的是将这些值合并到一个具有相同amendment计数的索引中

这是我预期的 output

 [
    {
       amendment: 1,
       lcnumber: "A1114564564CT",
       31D: "New Note",
       27: "0/0 (Number)(Total)",
    },
   {
      amendment: 2,
      lcnumber: "A1114564564CT",
      31D: "IN SINGAPORE (120 Days from L/C issue date)",
      32B: "USD",
      27: "2/2 (Number)(Total)",
      39B: "Exceeding"
   },
  ]

我试过写一个foreach循环，但这没有用

foreach($final_datas as $arrflight) {
    $final_array[] = (object) array(
        'lcnumber' => 'AZ300',
        $arrflight['swift_code'] => $arrflight['note']
    ); 
}

Answer 1

它并不完美，但它确实有效。 我相信有人会提供更清洁的解决方案。 我今天没有喝足够的咖啡。

$finalArray = [];
foreach ($originalArray as $arrParts) {
    if (!array_key_exists($arrParts["amendment"], $finalArray)) {
        $finalArray[$arrParts["amendment"]] = [];
    }
    foreach ($arrParts as $key => $value) {
        $finalArray[$arrParts["amendment"]][$key] = $value;
    }
}