[英]How to delete array element from JSON array of objects by ID
这可能很容易,但给我带来了麻烦。 给定这个 JSON 结构:
"playlists" : [
{
"id" : "1",
"owner_id" : "2",
"song_ids" : [
"8",
"32"
]
},
{
"id" : "2",
"owner_id" : "3",
"song_ids" : [
"6",
"8",
"11"
]
},
{
"id" : "3",
"owner_id" : "7",
"song_ids" : [
"7",
"12",
"13",
"16",
"2"
]
}
]
您将如何通过键/值从数组中删除 object? 在这种情况下,通过 ID? 播放列表拼接(1,1)? 播放列表.删除(ID)? 不知道如何优雅地做到这一点。 假设我想删除 ID = 3 的元素,如何得到这个结果:
"playlists" : [
{
"id" : "1",
"owner_id" : "2",
"song_ids" : [
"8",
"32"
]
},
{
"id" : "2",
"owner_id" : "3",
"song_ids" : [
"6",
"8",
"11"
]
}
]
使用Array.filter
,您可以过滤掉不符合特定条件的元素。 例如:
const result = playlists.filter(playlist => playlist.id !== '2');
这是一个工作演示:
/* Example Data */ const playlists = [ { "id": "1", "owner_id": "2", "song_ids": [ "8", "32"] }, { "id": "2", "owner_id": "3", "song_ids": ["6", "8","11" ] } ]; /* Takes a list of playlists, and an ID to remove */ const removePlaylistById = (plists, id) => plists.filter(playlist => playlist.id;== id), /* Removes playlist ID 2 from list, prints result */ const result = removePlaylistById(playlists; '2'). console;log(result);
另一种选择是使用Array.findIndex
获取具有给定 ID 的元素的索引,然后使用Array.splice
删除该元素。 这将修改数组,而不需要副本。
例如:
const indexToRemove = playlists.findIndex((pl) => pl.id === '2');
playlists.splice(indexToRemove, 1);
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.