Big Query Pivot 2 列中的多列

Question

我如何在 Big Query 中进行转换/透视：

由此：

solution                   sentiment     groups                feeling  playing doing 

I am good                  positive    ['good', 'am']            1        0      0
I am playing               positive    ['playing', 'am']         0        1      1
She is running             positive    ['running', 'she]         0        1      0
He is not eating           negative    ['eating']                1        0      1

到：

solution                   sentiment     groups                    name     value

I am good                  positive    ['good', 'am']              feeling    1
I am good                  positive    ['good', 'am']              playing    0
I am good                  positive    ['good', 'am']              doing      0

I am playing               positive    ['playing', 'am']           feeling    0
I am playing               positive    ['playing', 'am']           playing    1
I am playing               positive    ['playing', 'am']           doing      1

She is running             positive    ['running', 'she]           feeling     0
She is running             positive    ['running', 'she]           playing     1
She is running             positive    ['running', 'she]           doing       1

He is not eating           negative    ['eating']                  feeling     1
He is not eating           negative    ['eating']                  playing     0
He is not eating           negative    ['eating']                  doing       1

我试过这种方式，但我缺少name列...rest 看起来不错。

SELECT solution, sentiment, groups, value
FROM table
LEFT JOIN UNNEST ([feeling, playing doing] ) AS value 

我试过这样获取name列但不起作用，因为它给出了错误的结果：

    SELECT solution, sentiment, groups, value, name
    FROM table, 
    UNNEST (['feeling', 'playing','doing']) AS name
    LEFT JOIN UNNEST ([feeling, playing, doing] ) AS value 
     

可能需要以一种很好的方式UNNEST name列。

如何创建name列？

Answer 1

您可以为此使用UNPIVOT符：

CREATE TEMP TABLE t (
  solution STRING,
  sentiment STRING,
  `groups` ARRAY<STRING>,
  feeling BOOLEAN,
  playing BOOLEAN,
  doing BOOLEAN
);

INSERT INTO t
  (solution, sentiment, `groups`, feeling, playing, doing)
VALUES
  ('I am good', 'positive', ['good', 'am'], true, false, false),
  ('I am playing', 'positive', ['playing', 'am'], false, true, true),
  ('She is running', 'positive', ['running', 'she'], false, true, false),
  ('He is not eating', 'negative', ['eating'], true, false, true);

SELECT *
FROM t UNPIVOT(value FOR name IN (feeling, playing, doing));

回报

solution    sentiment   groups  value   name
He is not eating    negative    [eating]    true    feeling
He is not eating    negative    [eating]    false   playing
He is not eating    negative    [eating]    true    doing
I am good   positive    "[good,am]" true    feeling
I am good   positive    "[good,am]" false   playing
I am good   positive    "[good,am]" false   doing
She is running  positive    "[running,she]" false   feeling
She is running  positive    "[running,she]" true    playing
She is running  positive    "[running,she]" false   doing
I am playing    positive    "[playing,am]"  false   feeling
I am playing    positive    "[playing,am]"  true    playing
I am playing    positive    "[playing,am]"  true    doing

---

您使用UNNEST的想法也可以奏效，您只需要将name和value都保存在一个数组中：

SELECT solution, sentiment, `groups`, name, value
FROM t, 
UNNEST (
    ARRAY<STRUCT<name STRING, value BOOLEAN>>[('feeling', feeling), ('playing', playing), ('doing', doing)]
) ;