SQL查询——二选一

Question

如何将这两个选择合并为一个？ 结果，我想要列“POJ”、“锁定 POJ”和“EV”。

SELECT COUNT(VC) AS 'POJ', F.F_C.VC AS 'EV' FROM
F.F_D  LEFT JOIN F.F_C ON F.F_D.col_id = F.F_C.id
LEFT JOIN F.F_Z_D ON F.F_D.id = F.F_Z_D.id
where createdTime >= '2021-05-01' and createdTime <= '2022-05-31' and tTemplate = 'ZS' GROUP BY F.F_C.VC;

SELECT COUNT(VC) AS 'locked POJ', F.F_C.VC AS 'EV' FROM
F.F_D LEFT JOIN F.F_C ON F.F_D.col_id = F.F_C.id
LEFT JOIN F.F_Z_D ON F.F_D.id = F.F_Z_D.id
where createdTime >= '2021-05-01' and createdTime <= '2022-05-31' and tTemplate = 'ZS' and locked = 1 GROUP BY F.F_C.VC;

Answer 1

使用条件聚合：

SELECT COUNT(VC) AS POJ, SUM(locked = 1) AS `locked POJ`, F.F_C.VC AS EV
FROM F.F_D
LEFT JOIN F.F_C ON F.F_D.col_id = F.F_C.id
LEFT JOIN F.F_Z_D ON F.F_D.id = F.F_Z_D.id
WHERE createdTime BETWEEN '2021-05-01' AND '2022-05-31' AND tTemplate = 'ZS'
GROUP BY F.F_C.VC;

请注意，这两个查询之间的唯一区别是第二个查询在WHERE子句中具有附加条件locked = 1 。 我们可以删除它并使用第一个查询以及条件计数。