[英]Typescript types that can be overwritten based on type arguments
我试图找出告诉打字稿编译器返回T | null
的函数的最佳方法。 在某些情况下, T | null
肯定是T
也许我正在考虑这个错误,在这种情况下我也对新想法持开放态度,这里是片段:
type ValueOrNull<T, N> = N extends false ? T | null : T;
export function getCookie<T = any, N = false>(name: string): ValueOrNull<T, N> {
const match = document.cookie.match(new RegExp('(^| )' + name + '=([^;]+)'));
if (match) {
const [, , value] = match;
return parseCookieValue(value) as T;
}
return null;
}
我的想法是,如果我可以按如下方式调用该函数: getCookie<TMyCookie, true>("my_cookie")
打字稿会知道我确定 cookie 会在那里,并且该函数不会返回 null。 例如成功登录后。
N extends false ?
感觉不对,但N === false
不起作用。
编译器错误是Type 'null' is not assignable to type 'ValueOrNull<T, N>'.ts(2322)
非常感谢
您可以通过函数重载和第二个参数轻松地做到这一点; 当(不可避免地)程序员“知道”cookie存在但它不存在时,这也可以让您构建一个有用的解释性错误:
export function getCookie<T>(name: string, required: true): T;
export function getCookie<T>(name: string, required?: false): T | null;
export function getCookie<T>(name: string, required?: boolean): T | null {
const match = document.cookie.match(new RegExp('(^| )' + name + '=([^;]+)'));
if (match) {
const [, , value] = match;
// You'll want to put your `parseCookingvalue` back here,
// the `as any as T` is just because we don't have that
// function available to use in the question.
return /*parseCookieValue(value)*/ value as any as T;
} else if (required) {
throw new Error(`Required cookie "${name}" was not found`);
}
return null;
}
const a = getCookie<string>("a", true);
// ^? −−−− type is string
const b = getCookie<string>("b", false);
// ^? −−−− type is string | null
不过,这里有一个替代方案:您可以让getCookie
相当简单,并拥有一个通用类型断言函数,您可以在任何地方使用该函数,您可以返回可能为null
或undefined
并且您“知道”它不是null
或undefined
的东西:
export function getCookie<T>(name: string): T | null {
const match = document.cookie.match(new RegExp('(^| )' + name + '=([^;]+)'));
if (match) {
const [, , value] = match;
// You'll want to put your `parseCookingvalue` back here,
// the `as any as T` is just because we don't have that
// function available to use in the question.
return /*parseCookieValue(value)*/ value as any as T;
}
return null;
}
export function assertIsNotNullish<T>(value: T | null | undefined): asserts value is T {
if (value == null) {
throw new Error(`Expected non-nullish value, got ${value}`);
}
}
const a = getCookie<string>("a");
assertIsNotNullish(a);
console.log(a);
// ^? −−−− type is string
const b = getCookie<string>("b");
console.log(b);
// ^? −−−− type is string | null
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