[英]How to keep it a 2D array using filter()?
可能看起来很傻,但我没有找到任何不会诉诸其他功能的东西,所以......
ar1 = [[1, 10, "Item1", 50], [1, 10, "Item1", 50],[1, 10, "Item3", 50]];
let ar2 = ar1.filter(e => e[2] === "Item1")[0];//To get only of the filtered records
它返回:
[1, 10, "Item1", 50]
但要让它返回:
[[1, 10, "Item1", 50]]
谢谢!
也许是这样:
function lfunko() {
const a = [[1, 10, "Item1", 50], [1, 10, "Item1", 50],[1, 10, "Item3", 50]];
Logger.log(a.filter(r => r[2] == "Item1").filter((r,i) => i == 1));
}
Execution log
12:42:24 PM Notice Execution started
12:42:23 PM Info [[1.0, 10.0, Item1, 50.0]]
12:42:25 PM Notice Execution completed
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