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[英]My loop isn't separating the array items that don't match on the other array, how can I do that?
[英]How can I match items in my array with items in my object?
取如下数据结构
report = {
fraud_ids: [2, 3, 4, 15],
}
fraudTypes: {
ACH: {
fraud_category: "fraud",
fraud_subcategory: "a",
fraud_type_id: "4",
},
'Account takeover': {
fraud_category: "misc",
fraud_subcategory: "a",
fraud_type_id: "2",
},
'Advance fee': {
fraud_category: "fraud",
fraud_subcategory: "b",
fraud_type_id: "8",
},
'Against Financial Institution Customer(s)': {
fraud_category: "cyber",
fraud_subcategory: "b",
fraud_type_id: "15",
},
'Against Financial Institution(s)': {
fraud_category: "cyber",
fraud_subcategory: "a",
fraud_type_id: "78",
},
'Alters or cancels transaction to avoid BSA recordkeeping requirement': {
fraud_category: "structuring",
fraud_subcategory: "a",
fraud_type_id: "3",
},
}
我想通过欺诈类型 ID 将欺诈类型对象与数组中的正确数字相匹配。 当我找到匹配项时,我只想返回对象的键。
因此,使用上面的示例,我将返回['Account takeover', 'Alters or cancels transaction to avoid BSA recordkeeping requirement', 'ACH', Against Financial Institution Customer(s)']
我编写了以下逻辑,令我惊讶的是,我得到了一个包含四个返回未定义项的数组。
const x = report.fraud_ids.map(id => {
Object.keys(fraudTypes).map(fraudDescription => {
if (parseInt(fraudTypes[fraudDescription].fraud_type_id, 10) === id) {
return true;
}
});
});
我希望这会返回匹配的四个对象,然后我知道我必须编写额外的逻辑才能返回键。 我究竟做错了什么?
请参阅 代码沙盒。
您没有从第一个回调中返回任何内容, .map
也不是正确的内部方法 - 而是使用.find
来查找具有匹配 ID 的键。
report={fraud_ids:[2,3,4,15],fraudTypes:{ACH:{fraud_category:"fraud",fraud_subcategory:"a",fraud_type_id:"4"},"Account takeover":{fraud_category:"misc",fraud_subcategory:"a",fraud_type_id:"2"},"Advance fee":{fraud_category:"fraud",fraud_subcategory:"b",fraud_type_id:"8"},"Against Financial Institution Customer(s)":{fraud_category:"cyber",fraud_subcategory:"b",fraud_type_id:"15"},"Against Financial Institution(s)":{fraud_category:"cyber",fraud_subcategory:"a",fraud_type_id:"78"},"Alters or cancels transaction to avoid BSA recordkeeping requirement":{fraud_category:"structuring",fraud_subcategory:"a",fraud_type_id:"3"}}}; const x = report.fraud_ids.map(id => ( Object.keys(report.fraudTypes).find(fraudDescription => Number(report.fraudTypes[fraudDescription].fraud_type_id) === id) )); console.log(x);
我不知道这是否是你想要的,但它就是这样。
const selectedFrauds = report.fraud_ids.map((id, index) => {
return(
Object.values(fraudTypes).map((fraud, idx) => {
return id === +fraud.fraud_type_id ? fraud : "";
})
)
})
const cleanSelectedFrauds = selectedFrauds.map((el) => {
return el.filter((innerEl) => {
if(innerEl) {
return innerEl
}
})
});
console.log(cleanSelectedFrauds)
这将返回以下数组:
[
[
{
fraud_category: 'misc',
fraud_subcategory: 'a',
fraud_type_id: '2'
}
],
[
{
fraud_category: 'structuring',
fraud_subcategory: 'a',
fraud_type_id: '3'
}
],
[
{
fraud_category: 'fraud',
fraud_subcategory: 'a',
fraud_type_id: '4'
}
],
[
{
fraud_category: 'cyber',
fraud_subcategory: 'b',
fraud_type_id: '15'
}
]
]
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