有没有更好的方法通过对象的属性对对象进行排序？

Question

TL;博士

我如何（更好地）对对象的属性进行排序？

我不是试图按值或键对对象属性进行[排序] 。

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问题

我有一个对象（如下所示），我需要将属性（键/值对）移动到所述对象的开头。

// Pre-sorted! But can be in any arrangement due to a hidden `channel.live` property
// name: date
{
    // beginning
    "channel-1": "2022-06-29T11:20:14.000Z",
    "channel-2": "2022-06-29T05:58:18.000Z",
    "channel-3": "2022-06-29T05:18:49.000Z",
    "channel-4": "2022-06-29T04:08:35.000Z",
    "channel-5": "2022-06-29T01:52:31.000Z",
    "channel-6": "2022-06-29T01:00:40.000Z",
    "channel-7": "2022-06-29T00:59:47.000Z",
    "channel-8": "2022-06-29T00:07:28.000Z",
    "channel-9": "2022-06-28T23:55:27.000Z",
    // end
}

尝试过的解决方案

当前的解决方案是删除所有其他属性并重新添加它们（将它们放在末尾）。

例如，如果我删除channel-5并重新添加它，对象将被字符串化（通过JSON.stringify ）为{"channel-1":"..." ··· "channel-9":"...","channel-5":"..."} ，有效地将属性移动到末尾。

// Prioritize live channels!
// This will move a channel that isn't live to the end of the `Channels` object
if(!channel.live) {
    delete Channels[name];

    Channels[name] = date.toJSON();
}

Answer 1

由于您需要根据您的条件删除和添加频道，因此我提到了一种满足您要求的方法，它应该适合您。

let Channels = {
    "channel-1": "2022-06-29T11:20:14.000Z",
    "channel-2": "2022-06-29T05:58:18.000Z",
    "channel-3": "2022-06-29T05:18:49.000Z",
    "channel-4": "2022-06-29T04:08:35.000Z",
    "channel-5": "2022-06-29T01:52:31.000Z",
    "channel-6": "2022-06-29T01:00:40.000Z",
    "channel-7": "2022-06-29T00:59:47.000Z",
    "channel-8": "2022-06-29T00:07:28.000Z",
    "channel-9": "2022-06-28T23:55:27.000Z",
}

if(!channel.live) {
  delete Channels[name];
  Channels[name] = date.toJSON();
}

if(channel.live)
  Channels = { [name]: time.toJSON(), ...Channels };
}

const updatedChannels = {};
Object.keys(Channels).sort().forEach(item => (updatedChannels[item] = Channels[item]));

Channels = updatedChannels;

Answer 2

复制该死的对象...

// Prioritize live channels!
// This will move a channel that is live to the beginning of the `Channels` object
if(channel.live) {
    // Ensures `...Channels` doees NOT overwrite the new property
    delete Channels[name];

    Channels = { [name]: time.toJSON(), ...Channels };
}