[英]How to print character, Number and special character from given String in Java?
给定字符串是str = "aQt4512m@!%n"
输出:
character:aQtmn , Number:4512 special:@!%
下面是代码,我试过了,但它是唯一的打印字符
String str = "asDftQ32$34h";
char[] chArr = str.toCharArray();
Character myChar = '\0';
for(int i=0;i<chArr.length;i++) {
myChar = '\0';
if(chArr[i]>=65 && chArr[i]<=122) {
myChar =chArr[i];
}
String tr = myChar.toString();
String dr = tr.replaceAll("\\W","");
System.out.print(dr);
}
您可以像示例中那样使用 replaceAll() 来做到这一点:
public class Main {
public static void main( String[] arg ) {
String str = "aQt4512m@!%n";
String chars = str.replaceAll( "[\\W\\d]", "" );
System.out.println( chars );
String special = str.replaceAll( "\\w", "" );
System.out.println( special );
String numbers = str.replaceAll( "\\D", "" );
System.out.println( numbers );
}
}
检查此以获取有关正则表达式的更多信息: https ://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html
public void printString()
{
String input = "asDftQ32$34h";
List<Character> numbers = new ArrayList<>();
List<Character> letters = new ArrayList<>();
List<Character> specialChars = new ArrayList<>();
for (char current: input.toCharArray()) {
if(Character.isDigit(current))
{
numbers.add(current);
}
else if(Character.isAlphabetic(current))
{
letters.add(current);
}
else
specialChars.add(current);
}
System.out.println("All Letters In String :"+ letters);
System.out.println("All Numbers In String :"+ numbers);
System.out.println("All Special Characters In String :"+ specialChars);
}
使用字符 API
由于您显然被允许使用正则表达式,因此您可以使用字符类来完成以下工作:
String str = "asDftQ32$34h";
System.out.println("character: " + str.replaceAll("\\P{L}", ""));
System.out.println("number: " + str.replaceAll("\\P{N}", ""));
System.out.println("special: " + str.replaceAll("\\p{Alnum}", ""));
这是代码:
c
c
在 az 或 AZ 的范围内,它会附加到名为“characters”的 StringBuilderprivate static void separateCharacters(String str) {
StringBuilder characters = new StringBuilder();
StringBuilder digits = new StringBuilder();
StringBuilder special = new StringBuilder();
for (int i = 0; i < str.length(); i++) {
char c = str.charAt(i);
if (Character.isAlphabetic(c)) {
characters.append(c);
} else if (Character.isDigit(c)) {
digits.append(c);
} else if ((c >= 33 && c <= 47) ||
(c >= 58 && c <= 64) ||
(c >= 91 && c <= 96) ||
(c >= 123 && c <= 126)) {
special.append(c);
} else {
System.out.println("skipping character: " + c);
}
}
System.out.println("characters : " + characters);
System.out.println("digits : " + digits);
System.out.println("special : " + special);
}
这是一个输出“aQt4512m@!%n”的运行:
separateCharacters("aQt4512m@!%n");
characters : aQtmn
digits : 4512
special : @!%
同样,这次是“aQt4512m@!%n[-=":
separateCharacters("azrRt07572m@!%n[-=");
characters : azrRtmn
digits : 07572
special : @!%[-=
我不喜欢“特殊”处理,但这应该足以说明如何修改代码以包含/排除任何不同组的其他字符。 或者,您可以选择遵循所有非字母、非数字字符都是“特殊”的逻辑,在这种情况下,您可以将默认的“else”语句设置为special.append(c)
。
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