具有多个值的过滤器数组

Question

假设我有一组电子邮件，我想过滤一个特定的域，例如：

  
 
  
  
  
 
   
 
    
const emails = ['test@hotmail.com', 'test@gmail.com', 'test@yahoo.com']
const excludedDomain = '@hotmail';
// This works fine
const eligibleEmails = emails.filter(email => !emails.includes(excludedDomain));
console.log(eligibleEmails);
 
   
 
  

我尝试使用some() ，但它返回一个布尔值，我需要返回一个新的过滤数组。 试图混合filter()和some()但没有用。

Answer 1

将filter()与some()和includes()结合以检查我们正在过滤的当前电子邮件中是否有任何excludedDomains includes()

 const emails = ['test@hotmail.com', 'test@gmail.com', 'test@yahoo.com'] const excludedDomains = ['@hotmail', '@yahoo']; const eligibleEmails = emails.filter(e => !excludedDomains.some(ee => e.includes(ee))); console.log(eligibleEmails);

Answer 2

只需在原始过滤器内的 excludeDomain 上使用另一个过滤器。

const emails = ['test@hotmail.com', 'test@gmail.com', 'test@yahoo.com'];
const excludedDomains = ['@hotmail', '@yahoo'];

const filtered = emails.filter(email => 
  excludedDomains.filter(ed => email.includes(ed)).length === 0
)

console.log(filtered); // [ 'test@gmail.com' ]

Answer 3

以下代码段按 excludeDomains 过滤电子邮件以返回符合条件的电子邮件。

 const emails = ['test@hotmail.com', 'test@gmail.com', 'test@yahoo.com'], excludedDomain = ['@hotmail', '@yahoo'], eligibleEmails = emails.filter(email => excludedDomain.some(str => email.indexOf(str) > -1)); console.log(eligibleEmails);