Array.Filter() 使用回调函数比较两个数组

Question

Insted 使用匿名函数如何将以下元素 => arr2.includes(element) 转换为命名函数，然后我可以传入

  const ArrayOverlap = (arr1, arr2) =>{
  let newArr = [];
  return newArr = arr1.filter(element => arr2.includes(element));
}

如果我要做类似的事情

  const ArrayOverlap = (arr1, arr2) =>{
  let newArr = [];
  return newArr = arr1.filter(bothIncluded(arr1, arr2));
}

 function bothIncluded(arr1, arr2){
  for(const item of arr1){
   return arr2.includes(item);
}

Answer 1

在调用回调函数时，我可以通过使用选项 thisArg 让它工作。

const ArrayOverlap = (arr1, arr2) =>{
let newArr = [];
return newArr = arr1.filter(checkMe, arr2);

function checkMe(element){
return this.includes(element);
}