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[英]How group primary keys with different value but same name and using datediff
[英]How to perform UNION of the tables with same column name as their primary keys but different values
这是两张表: 输入:
Employees table:
+-------------+----------+
| employee_id | name |
+-------------+----------+
| 2 | Crew |
| 4 | Haven |
| 5 | Kristian |
+-------------+----------+
Salaries table:
+-------------+--------+
| employee_id | salary |
+-------------+--------+
| 5 | 76071 |
| 1 | 22517 |
| 4 | 63539 |
+-------------+--------+
我想要一个输出,比如你如何执行加入但使用联合。
联合的输出应如下所示:
employee_id | name | salary
2 crew. null
4. haven. 63539
5. Kristian 76071
1. null. 22517
并发布我想要执行选择的工会,方法是选择没有姓名或没有薪水的员工的employee_id
目前我正在处理的查询:
select * from
(select employee_id, name, null as salary from employees
union all
select employee_id, null as name, salary from salaries)
as emp
where name is null or salary is null
结果如下所示:
{"headers": ["employee_id", "name", "salary"], "values": [[2, "Crew", null], [4, "Haven", null], [5, "Kristian" , null], [5, null, 76071], [1, null, 22517], [4, null, 63539]]}
如果使用此查询:
select * from (selectemployee_id, name from employees union all selectemployee_id,salary from paid) as emp
结果如下所示:
{"headers": ["employee_id", "name"], "values": [[2, "Crew"], [4, "Haven"], [5, "Kristian"], [5, "76071" ], [1, "22517"], [4, "63539"]]}
这是一个完整的联接:
Select coalesce(e.employeeid, s.employeeid) employed
e.name, e.salary
From employees e full join
Salaries s
On e.employeeid = s.employeeid
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