[英]Add Column to Result of Postgres Dynamic Query
我有一个看起来像这样的表:
| Scenario| Date | System | Result |
| ------- | ------ | ------ | ------ |
| Proj1 | 07-01 | A | PASS |
| Proj1 | 07-01 | B | PASS |
| Proj1 | 07-01 | C | PASS |
| Proj1 | 07-01 | D | PASS |
| Proj1 | 07-02 | A | FAIL |
| Proj1 | 07-02 | B | FAIL |
| Proj1 | 07-02 | C | FAIL |
| Proj1 | 07-02 | D | FAIL |
| Proj2 | 07-01 | E | PASS |
| Proj2 | 07-01 | F | FAIL |
| Proj2 | 07-02 | E | PASS |
| Proj2 | 07-02 | F | PASS |
我将其重新排列为:
| Project | Date | System1 | System2 | System3 | System4| Overall|
| ------- | ---- | ------- | ------- | ------- | -------|--------|
| Proj1 | 07-01| A-PASS | B-PASS | C-PASS | D-PASS |PASS |
| Proj1 | 07-02| A-FAIL | B-FAIL | C-FAIL | D-FAIL |FAIL |
| Proj2 | 07-01| E-PASS | F-FAIL | | |FAIL |
| Proj2 | 07-02| E-PASS | F-PASS | | |PASS |
我想根据上表创建一个包含此数据的图表
|Date |# of Passes|# of Fails|
|------|-----------|----------|
|07-01 | 1 | 1 |
|07-02 | 1 | 1 |
您可以通过Count(*) over (Partition By Scenario,Date)
来找到特定 (Date,Scenario) 的所有系统的计数,并通过使用Aggregate Filter
作为该 (Date,Scenario) 仅通过系统的计数以下, count(*) filter (where Result='PASS') over (Partition By Scenario,Date)
。
然后比较两个计数,如果它们相等,则将整体结果设置为PASS
。
考虑以下:
Create Or Replace Function pvt()
RETURNS void
LANGUAGE 'plpgsql'
As $body$
declare
sqlColumn varchar;
qr varchar;
columnlist varchar;
Begin
sqlColumn= 'select distinct D.sys_cat from (select Row_Number() Over (Partition By Scenario,Date Order By System) as sys_cat From run) D order by D.sys_cat;';
qr='prepare pvtstmt AS Select D.Scenario,D.Date,';
For columnlist In EXECUTE sqlColumn
Loop
qr=qr || 'Max(Case When sys_cat=' || columnlist || ' Then (System || ''_'' || Result) Else '''' End) As System' || columnlist || ' , ';
END LOOP;
--qr=substr(qr, 0, length(qr) - 1);
qr=qr|| 'case when D.tc= D.pc then ''PASS'' else ''FAIL'' end as overall ';
qr=qr || 'From (select *, Count(*) over (Partition By Scenario,Date) tc,'||
' count(*) filter (where Result=''PASS'') over (Partition By Scenario,Date) pc,'||
' Row_Number() Over (Partition By Scenario,Date Order By System) as sys_cat From run) D Where D.Scenario ='
|| '''Proj1'' Group By D.Scenario,D.Date,overall Order By D.Scenario,D.Date';
Deallocate All;
EXECUTE qr;
End;
$body$
查看db<>fiddle的演示。
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