[英]App not retrieving images from firebase realtime database in android studio with Java
[英]when retrieving a link from realtime database to android studio it adds a tag
所以基本上当我从我的实时数据库中检索一个链接时,它会在开头添加这个“{abs =”,在最后添加这个“}”,这使得毕加索无法加载链接。 我尝试通过将链接直接粘贴到毕加索来加载链接,它工作得很好这是我的代码的副本:
public class MainActivity extends AppCompatActivity {
private Button button;
private TextView tv0, tv1;
private String string;
private ImageView imageView;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
tv0 = findViewById(R.id.textView);
imageView = findViewById(R.id.imageView);
tv1 = findViewById(R.id.textView2);
button = findViewById(R.id.button);
button.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
DatabaseReference reference = FirebaseDatabase.getInstance().getReference().child("muscles");
reference.addValueEventListener(new ValueEventListener() {
@Override
public void onDataChange(@NonNull DataSnapshot snapshot) {
for (DataSnapshot dataSnapshot : snapshot.getChildren()) {
string = snapshot.getValue().toString();
}
tv1.setText(string);
tv0.setText("{abs=https://firebasestorage.googleapis.com/v0/b/my-application-5272b.appspot.com/o/ts-space-sun-and-solar-viewing-facts-versus-fiction.webp?alt=media&token=264af080-27a5-4177-ade3-6eaf30125383}");
Picasso.get().load("https://firebasestorage.googleapis.com/v0/b/my-application-5272b.appspot.com/o/ts-space-sun-and-solar-viewing-facts-versus-fiction.webp?alt=media&token=264af080-27a5-4177-ade3-6eaf30125383").into(imageView);
}
@Override
public void onCancelled(@NonNull DatabaseError error) {
}
});
}
});
}
这是 XML 代码:`
<android.widget.Button
android:id="@+id/button"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:background="@drawable/button"
android:text="Button"
android:textColor="@color/white"
app:layout_constraintBottom_toTopOf="@+id/textView2"
app:layout_constraintEnd_toEndOf="parent"
app:layout_constraintStart_toStartOf="parent"
app:layout_constraintTop_toBottomOf="@+id/textView" />
<TextView
android:id="@+id/textView"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="tt"
app:layout_constraintEnd_toEndOf="parent"
app:layout_constraintStart_toStartOf="parent"
app:layout_constraintTop_toTopOf="parent" />
<TextView
android:id="@+id/textView2"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="TextView"
app:layout_constraintBottom_toBottomOf="parent"
app:layout_constraintEnd_toEndOf="parent"
app:layout_constraintStart_toStartOf="parent" />
<ImageView
android:id="@+id/imageView"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
app:layout_constraintBottom_toTopOf="@+id/button"
app:layout_constraintEnd_toEndOf="parent"
app:layout_constraintHorizontal_bias="0.498"
app:layout_constraintStart_toStartOf="parent"
app:layout_constraintTop_toTopOf="parent"
app:layout_constraintVertical_bias="0.593"
tools:srcCompat="@tools:sample/avatars" />
</androidx.constraintlayout.widget.ConstraintLayout>`
问题在这里:
public void onDataChange(@NonNull DataSnapshot snapshot) {
for (DataSnapshot dataSnapshot : snapshot.getChildren()) {
string = snapshot.getValue().toString();
}
当您循环从数据库获取的快照以到达各个子节点时,您实际上总是获得父节点的值。
要解决这个问题:
public void onDataChange(@NonNull DataSnapshot snapshot) {
for (DataSnapshot dataSnapshot : snapshot.getChildren()) {
string = dataSnapshot.getValue().toString();
// 👆
}
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