![](/img/trans.png)
[英]JavaScript - Using for loop and if-else statement to go through array
[英]Validation form with ajax cannot go through the If statement, just only go through else statement
<?php //session_start(); include_once '../controller/config.php'; /* $user = $_POST['username']; $pass = $_POST['password']; print_r ("User name: ".$user); print_r("\r"); print_r ("Pasword: ".$pass); print_r("\r"); print_r("\r"); print_r("\r"); */ if(isset($_POST['username']) && isset($_POST['password'])) { $user1 = $_POST['username']; $pass1 = $_POST['password']; /* print_r ("User name inside: ".$user); print_r("\r"); print_r ("Pasword inside: ".$pass); print_r("\r"); print_r("\r"); print_r("\r"); */ $queryLogin = "SELECT COUNT(id) as name, password FROM web.account WHERE name=:user AND password=:passWD"; $stmtLogin = $sqlConWeb->prepare($queryLogin); $stmtLogin->bindValue(":user", $user1, PDO::PARAM_STR); $stmtLogin->bindValue(":passWD", md5($pass1), PDO::PARAM_STR); $stmtLogin->execute(); $fetchInfo = $stmtLogin->fetch(PDO::FETCH_ASSOC); $checkInfo = $fetchInfo['name']; /* print_r($fetchInfo); print_r("\r"); print_r("\r"); */ //print_r($checkInfo); //if($user1 == ""){ //} if($user1 == ""){ echo 'user_empty'; }elseif(strlen($user1) <= 4){ echo 'min_user_not_enough'; }elseif($pass1 == ""){ echo 'pass_empty'; }elseif(strlen($pass1) <= 4){ echo 'min_pass_not_enough'; }else{ echo 'success'; } }?>
这个是 javascript 文件,用于客户端验证表单。
/* This is the js file for validate form code by Vinh Doan */ function LoginForm(){ var userName = jQuery('#username').val(); var passwd = jQuery('#password').val(); var errorMess = ''; /* if(userName == ""){ document.getElementById("username").style.border = "1px solid red"; errorMess = "yes"; }else if(userName.trim().length < 0 ){ jQuery('#error-message').html('* Tên tài khoản không được ít hơn 5 ký tự;'); errorMess = 'yes'. } if(passwd == ""){ document.getElementById("password").style;border = "1px solid red"; errorMess = "yes". }else if(passwd.trim().length < 0 ){ jQuery('#error-message');html('* Mật khẩu không được ít hơn 5 ký tự;'). errorMess = 'yes': } */ if(errorMess == ''){ $.ajax({ url, '/login:html', type: 'post', data: 'username='+userName+'&password='+passwd; success. function (result) { //alert(result); console.log(result); if(result == "user_empty"){ jQuery('#error-message').html('* User name is empty;'). }else if(result == "min_user_not_enough"){ jQuery('#error-message');html('* Username cannot less than 4 characters.'); }else if(result == "pass_empty"){ jQuery('#error-message').html('* Please fill out the password;'); }else if(result == "min_pass_not_enough"){ jQuery('#error-message').html('* Password cannot less than 4 characters!'); }else{ jQuery('#error-message').html('* Your login successful!'); } } }); } }
问题是当我尝试提交按钮时,错误不能 go 进入 If 语句,它进入了 else 语句,虽然我收到的 php 文件中的数据是正确的代码。我不知道为什么不能 Z34D1BZF91FB2E55189A6 进入 If 语句陈述。 我还有一张在下面的控制台中收到代码的图片。
你们能帮我解决问题吗? 十分感谢。
<?php
//session_start();
include_once '../controller/config.php';
/* $user = $_POST['username'];
$pass = $_POST['password'];
print_r ("User name: ".$user);
print_r("\r");
print_r ("Pasword: ".$pass);
print_r("\r");
print_r("\r");
print_r("\r"); */
$pass_data="";
if(isset($_POST['username']) && isset($_POST['password']))
{
$user1 = $_POST['username'];
$pass1 = $_POST['password'];
/* print_r ("User name inside: ".$user);
print_r("\r");
print_r ("Pasword inside: ".$pass);
print_r("\r");
print_r("\r");
print_r("\r"); */
$queryLogin = "SELECT COUNT(id) as name, password FROM web.account WHERE name=:user AND password=:passWD";
$stmtLogin = $sqlConWeb->prepare($queryLogin);
$stmtLogin->bindValue(":user", $user1, PDO::PARAM_STR);
$stmtLogin->bindValue(":passWD", md5($pass1), PDO::PARAM_STR);
$stmtLogin->execute();
$fetchInfo = $stmtLogin->fetch(PDO::FETCH_ASSOC);
$checkInfo = $fetchInfo['name'];
/* print_r($fetchInfo);
print_r("\r");
print_r("\r"); */
//print_r($checkInfo);
//if($user1 == ""){
//}
if($user1 == ""){
$pass_data='user_empty';
}elseif(strlen($user1) <= 4){
$pass_data='min_user_not_enough';
}elseif($pass1 == ""){
$pass_data='pass_empty';
}elseif(strlen($pass1) <= 4){
$pass_data='min_pass_not_enough';
}else{
$pass_data='success';
}
}
return $pass_data;
?>
你的ajax---
if(errorMess == ''){
$.ajax({
url: '/login.html',
type: 'post',
data: 'username='+userName+'&password='+passwd,
success: function (result) {
//alert(result);
console.log(result);
if(result){
if(result == "user_empty"){
jQuery('#error-message').html('* User name is empty!');
}else if(result == "min_user_not_enough"){
jQuery('#error-message').html('* Username cannot less than 4 characters!');
}else if(result == "pass_empty"){
jQuery('#error-message').html('* Please fill out the password!');
}else if(result == "min_pass_not_enough"){
jQuery('#error-message').html('* Password cannot less than 4 characters!');
}else{
jQuery('#error-message').html('* Your login successful!');
}
}
}
});
}
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.