[英]Php inside foreach loop if $i == 1 echo “ok”, else echo “ok” JUST one time and continue
[英]If all is OK echo ok but if one of all is not echo not ok
例如我会写 $data = [ok,ok,ok,ok,ok] 我想回显“ok”
但如果 $data = [ok,ok,ok,not,ok] 我想回应“not ok”
我需要帮助。
计数是否所有值都“ok”。
$data = ['ok', 'ok', 'ok', 'ok', 'ok'];
echo count(array_filter($data, fn($v) => $v !== 'ok')) ? 'not ok' : 'ok', PHP_EOL;
$data = ['ok', 'ok', 'ok', 'not', 'ok'];
echo count(array_filter($data, fn($v) => $v !== 'ok')) ? 'not ok' : 'ok', PHP_EOL;
回声
ok
not ok
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