插入和返回多个值 SQL

Question

我有两个关系一对多的表，我希望 INSERT 到mytable一些值并将多个值返回到变量中以便以后使用它们。 这里的例子：

 IF NOT EXISTS
        (SELECT id FROM mytable WHERE label_id = xxx)
    THEN
        INSERT INTO mytable
        (label_id, "name")
        VALUES
        (xxx,'foo'),
        (xxx,'bar')
    RETURNING 
        (SELECT id INTO mytable_id1 FROM mytable WHERE name = 'foo'),
        (SELECT id INTO mytable_id2 FROM mytable WHERE name = 'bar');
    ELSE 
        (SELECT id INTO mytable_id1 FROM mytable WHERE name = 'foo'),
        (SELECT id INTO mytable_id2 FROM mytable WHERE name = 'bar');
 END IF;

但我总是出错：

错误：在“进入”处或附近多次指定 INTO

我尝试 google 问题，例如INSERT INTO... RETURNING multiple columns (PostgreSQL)和Error: INTO 在“INTO”或附近指定了不止一次

不幸的是，解决方案对我没有帮助（或者我做错了什么）。 有任何想法吗？

Answer 1

我采取了另一种方式，为每个变量单独设置了一个IF 。 不是很聪明，但它的工作

 IF NOT EXISTS
        (SELECT id FROM mytable WHERE label_id = xxx and "name"='foo')
    THEN
        INSERT INTO mytable
        (label_id, "name")
        VALUES
        (xxx,'foo'),
    RETURNING 
        (SELECT id INTO mytable_id1 FROM mytable WHERE name = 'foo');
    ELSE 
        (SELECT id INTO mytable_id1 FROM mytable WHERE name = 'foo');
 END IF;
 IF NOT EXISTS
        (SELECT id FROM mytable WHERE label_id = xxx and "name"='bar')
    THEN
        INSERT INTO mytable
        (label_id, "name")
        VALUES
        (xxx,'bar'),
    RETURNING 
        (SELECT id INTO mytable_id1 FROM mytable WHERE name = 'bar');
    ELSE 
        (SELECT id INTO mytable_id1 FROM mytable WHERE name = 'bar');
 END IF;