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[英]VBA - search a string in row then copy & paste it to a different column
[英]VBA search string and copy row
我从一个表格开始,其中包含一个名称,该名称对应于工作代码和所述工作的开始日期。 见下文:
预期的结果是几乎翻转它(它正在成为更大宏的一部分,为此必须使用 VBA)
我需要列标题的日期和唯一名称列表。 列中将显示该日期的工作。 请参阅下面的示例:
我已经能够获得 select 所有包含人名的行的代码,但是我无法通过每个选定的行来逐一练习 go,复制工作代码并将其粘贴到下的新表中正确的对应日期。
由于某些工作有多个人,此代码使用 InStr() 来查找出现的 unqiue 名称
Sub NewTable()
Dim Rng As Range
Dim Cell As Object
Dim Found As Range
Dim Ws As Worksheet
Set Ws = Worksheets("Sheet1")
Set Rng = Ws.Range("D:D")
searchString = "Emily"
For Each Cell In Rng
If InStr(Cell, searchString) > 0 Then
If Not Found Is Nothing Then
Set Found = Union(myUnion, Cell.EntireRow)
Else
Set Found = Cell.EntireRow
End If
End If
Next
If Found Is Nothing Then
MsgBox "The text was not found in the selection"
Else
Found.Select
End If
End Sub
任何帮助,将不胜感激
试试这个:
Sub Tester()
Dim rw As Range, wsData As Worksheet, wsPivot As Worksheet, arr, e, r, c
Set wsData = ThisWorkbook.Worksheets("Input") 'sheet with original data
Set wsPivot = ThisWorkbook.Worksheets("Pivot") 'sheet for the final table
'loop over each row in the input table
For Each rw In wsData.Range("B6:E" & wsData.Cells(Rows.Count, "B").End(xlUp).Row).Rows
If Application.CountA(rw) = 3 Then 'row has data?
'try to match the date: add as new date if no match
c = Application.Match(CLng(rw.Cells(3).Value), wsPivot.Rows(1), 0)
If IsError(c) Then
c = wsPivot.Cells(1, Columns.Count).End(xlToLeft).Column + 1
If c < 4 Then c = 4 'dates start in D1
wsPivot.Cells(1, c).Value = rw.Cells(3).Value 'add the date
End If
arr = Split(rw.Cells(2).Value, ",") 'get array of all names
'check row for each name: add as new name if no match
For Each e In arr
'look for the name in Col B
r = Application.Match(Trim(e), wsPivot.Columns("B"), 0)
'if name not found, then add it in the next empty cell
If IsError(r) Then
r = wsPivot.Cells(Rows.Count, "B").End(xlUp).Row + 1
If r < 4 Then r = 4 'names begin in B4
wsPivot.Cells(r, "B").Value = e
End If
wsPivot.Cells(r, c).Value = rw.Cells(1).Value 'add the Job Code
Next e
End If
Next rw
End Sub
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