如何发送我的 MySQL 查询的结果？

Question

我正在开发一个带有 discordjs 和 mysql 的 Discord Bot，我想问一下如何将我的查询结果发送给请求它的用户。 我的代码如下所示：如果您有任何解决方案或想法，请与我分享。 （我在顶部删除了一点代码）

const conn = mysql.createConnection({
    host: "/",
    user: "/",
    password: "/",
    database: "/"
});


client.on('interactionCreate', async interaction => {
    if (!interaction.isChatInputCommand()) return;
    const { commandName } = interaction;
    if (commandName === 'submit') {
        conn.query(`INSERT INTO discordtest(userID, tag) VALUES ('${interaction.user.id}' , '${interaction.user.tag}')`)
        await interaction.reply(':white_check_mark: Daten erfolgreich hinterlegt!');
        interaction.channel.send({ embeds: [exampleEmbed] });
    }
        
    else if(commandName === 'info'){
    

conn.query(`SELECT licenses FROM discordtest WHERE userID=${interaction.user.id}`, (err, msg) =>{ 
            var message = msg.content;
                     if(err){
                    console.log(err)
                  }else
                console.log(msg)
            });

    const infoEmbed = new EmbedBuilder()
    .setColor(0x0099FF)
    .setTitle('Webseite')
    .setURL('https://zockercraft.de/')
    .setAuthor({ name: 'User Info', iconURL: 'https://zockercraft.de/discordbild/bild.jpg'})
    .setDescription(`Hier sind die Daten zu ${interaction.user.tag}:`)
    .setThumbnail(interaction.user.avatarURL())
    .addFields(
        { name: 'Test', value: 'test' , inline: true },
        { name: 'Test', value: 'Some value here', inline: true },
    )
    .setTimestamp()
    .setFooter({ text: 'Designed by: DerBZocker2#9955'
});
    await interaction.reply({ embeds: [infoEmbed] }); 
 
 
    }
});``` 

Answer 1

conn.query(`SELECT licenses FROM discordtest WHERE userID='${interaction.user.id}'`, (err, msg) => { 
    var message = msg.content; //What is this for?
    if(err) {
        console.log(err)
    } else {
        const embed = new EmbedBuilder()
        .setDescription(`${msg.userID}`) //msg will give you the details 
        //of your informations. connecting with '.' then add 'userID'
        .setColor(0x0099FF)
        .setTitle('Webseite')

        await interaction.reply({ embeds: [infoEmbed] }); 
    }
});

我对交互命令只有一点了解。 但我认为你只需要获取数据。 所以它应该做的伎俩