如何显示包含字符数组中所有字符的字符串列表中的字符串？ c#

Question

我有一个字符串列表和一个 char 字母数组。 我想在字符串中显示包含数组中所有字符的字符串。

List-list of strings charsArray-array of chars Final-带有排序单词的最终列表

例子

charsArray  {'a','e','i','z'}
List {"abcde","iertaz","aio","zzeml","amoioze"}
Final(output)  iertaz amoioze

我试过这个

foreach(string word in List)
{
    bool contain = true;
    foreach (char letter in charsArray}
    {
        if (word.Contains(letter) && contain)
        {
            Final.Add(word);
        }
        else
        {
            contain = false;

        }

    }

}
foreach (string word in Final)
{
    Console.WriteLine(word);
}

Answer 1

有

char[] chars = new char[] {
  'a','e','i','z'};

List<string> list = new List<string>() {
  "abcde", "iertaz", "aio", "zzeml", "amoioze" };

我们可以尝试从chars中减去word ：如果chars中的所有字符都被删除，那么这个word就是我们想要的：

using System.Linq;

...

var result = list
  .Where(word => !chars.Except(word).Any())
  .ToList();

Answer 2

此解决方案使用All ：

var charsArray = new char[] { 'a', 'e', 'i', 'z' };
var L = new[] { "abcde","iertaz","aio","zzeml","amoioze"}.ToList();

var final = L.Where(word => charsArray.All(a => word.Contains(a))).ToList();

结果是正确的：
伊尔塔兹
阿莫伊泽

Answer 3

这个怎么样，在这里演示

public static IEnumerable<IEnumerable<T>> ContainsAll<T>(
                                            this IEnumerable<IEnumerable<T>> source,
                                            IEnumerable<T> search,
                                            IEqualityComparer<T> comparer = default)
{
    ArgumentNullException.ThrowIfNull(source);
    ArgumentNullException.ThrowIfNull(search);
    comparer ??= EqualityComparer<T>.Default;
    
    var searchSet = search is HashSet<T> ss && ss.Comparer == comparer
        ? ss
        : new HashSet<T>(search, comparer);

    return source.Where(item => searchSet.IsSubsetOf(item));
}

你可以这样使用，

var words = new[] {"abcde","iertaz","aio","zzeml","amoioze"};
var search = new[] {'a','e','i','z'};
foreach (string match in words.ContainsAll(search))
{
    Console.WriteLine(match);
}

Answer 4

如果第一个字符在单词中，则在此行中添加单词，因为 contains 为真

...
if (word.Contains(letter) && contain)
        {
            Final.Add(word);
        }
...

你快到了，你只需要稍作修改就可以避免上面的错误

foreach(string word in List)
{
    bool contain = true;
    foreach (char letter in charsArray}
    {
        if (!word.Contains(letter))
        {
            contain = false;
        }
    }

  if (contain) 
  {
    Final.Add(word);
  }

}
foreach (string word in Final)
{
    Console.WriteLine(word);
}

Answer 5

您想查找包含charsArray中所有字符的字符串。 这意味着charsArray中的每个字符都应包含在目标字符串中。

using System.Linq;

var List = new List<string>() { "abcde", "iertaz", "aio", "zzeml", "amoioze" };
var charsArray = new char[] { 'a','e','i','z' };
var result = List.FindAll(word => charsArray.All(letter => word.Contains(letter)));