更新firebase云function数据库太慢

Question

I use firebase cloud function and firebase realtime database for my e-commerce.I have a problem on my function, when i run the function, i watch the realtime database and see changes made too late(10-15 sec). 我错了还是错过了某个地方？

firebase function：

app.post('/test', async (req:any, res:any) => {
  console.log("1")
  await iyzipay.checkoutForm.retrieve({
    locale: Iyzipay.LOCALE.TR,
    conversationId: '123456789',
    token: req.body.token
},  (err:any, result:any) => {
  if (result.paymentStatus = "SUCCESS") {
   admin.database().ref("tokens/"+req.body.token).once("value",async snap=>{
console.log("2")
    const userID = snap.child("who").val()
    admin.database().ref("users/"+userID+"/shopCart").remove()
    const snapshot =  await admin.database().ref("users/"+userID+"/copyShopCart/"+req.body.token).once("value")
    const array:any = []

   await snapshot.forEach(child  => {array.push(child)})
console.log("3")
      for await (const child of array) {
console.log("4")
        admin.database().ref("collections/"+child.key).once("value",async snap=>{

          var xs:number = snap.child("stock").child("xs").val()-(child.child("xs").val() || 0)
          var s:number = snap.child("stock").child("s").val()-(child.child("s").val() || 0)
          var m:number = snap.child("stock").child("m").val()-(child.child("m").val() || 0)
         
          admin.database().ref("collections/"+child.key+"/stock").update({xs:xs,s:s,m:m})
console.log("5")
      })
      }
console.log("6")
      await admin.database().ref("users/"+userID+"/myOrders").update(snapshot.val())//My orders

   })
 }
});
  await console.log("7")
res.redirect('http://localhost:4200/home')
res.end("...");
  });

  exports.widgets = functions.region('europe-west1').https.onRequest(app);

firebase function 日志：

Answer 1

在所有 Firebase 函数中，我们在返回值或 promise 完成并返回时终止 function。 When you execute an asynchronous operation in a background triggered Cloud Function, you must return a promise, in such a way the Cloud Function waits until this promise resolves in order to terminate.

通常会发生此问题，因为部分代码在asynchronous回调或 Promise 中执行，但已返回值或到达 function 的末尾。

为了使您的 function 成功完成，应解决承诺，使其不会在未完成工作的情况下终止 function。

句法：

const Promise1 = new Promise((resolve, reject) => {
  setTimeout(() => {
    resolve('new');
  }, 300);
});

Promise1
  .then(Resolved1, Rejected1)
  .then(Resolved2, Rejected2)
  .then(Resolved3, Rejected3);

有关更多信息，您可以参考这些 StackOverflow thread1 、 thread2和thread3以及这些文档以及document1和document2