遍历 laravel 中的集合并聚合它

Question

我有一个样本集

#items: array:4 [▼
0 => Collection {#465 ▼
  #items: array:2 [▼
    "id" => 1
    "user_id" => 5
  ]
}
1 => Collection {#455 ▼
  #items: array:2 [▼
    "id" => 2
    "user_id" => 5
  ]
}
2 => Collection {#419 ▼
  #items: array:2 [▼
    "id" => 3
    "user_id" => 1
  ]
}
3 => Collection {#410 ▼
  #items: array:2 [▼
    "id" => 4
    "user_id" => 1
  ]
}
]
}

如何将上述集合聚合到以下集合。 它是每个 user_id 的 id 计数。

#items: array:2 [▼
0 => Collection {#465 ▼
  #items: array:2 [▼
    "user_id" => 1
    "count" => 2
  ]
}
1 => Collection {#455 ▼
  #items: array:2 [▼
    "user_id" => 5
    "count" => 2
  ]
}
]
}

任何建议，将不胜感激。

Answer 1

我使用以下代码重新创建了该集合。

$collection = collect([
    collect(['id' => 1, 'user_id' => 5]),
    collect(['id' => 2, 'user_id' => 5]),
    collect(['id' => 3, 'user_id' => 1]),
    collect(['id' => 4, 'user_id' => 1]),
]);

假设这种结构，您可以通过链接几个方法来获得结果。

use Illuminate\Support\Collection;

$collection
    ->groupBy('user_id')
    ->map(fn ($item, $key) => ['user_id' => $key, 'count' => $item->count()])
    ->values();
    // ->mapInto(Collection::class); // if you really need each item to be its own collection

Answer 2

或者，您可以运行：

$result = array_values($collection->reduce(function (array $carry, $item) {
    $user_id = $item->first(fn($v, $k) => $k === "user_id");

    if (array_key_exists($user_id, $carry)) {
        $carry[$user_id]["count"]++;
    } else {
        $carry[$user_id] = [
            "user_id" => $user_id,
            "count" => 1,
        ];
    }
    return $carry;
}, []));