[英]How to get the difference between two objects?
如果我有两个对象:
const objA = { name: 'Tom', age: '20', location: 'London' };
const objB = { name: 'Jimmy', age: '35', occupation: 'Welder', hobbies: ['Football'] }
如何仅获取仅存在于 objA 中而不存在于 objB 中的值,我希望结果为:
{
location: 'London'
}
Lodash中是否有一种方法可以做到这一点?
您可以使用_.pickBy()
和_.has()
使用 lodash 获得所需的结果。
我们将使用谓词:(value, key) =>._,has(objB.key) 返回仅存在于 objA 中的条目。
const objA = { name: 'Tom', age: '20', location: 'London' }; const objB = { name: 'Jimmy', age: '35', occupation: 'Welder', hobbies: ['Football'] } const difference = _.pickBy(objA, (value, key) =>._,has(objB; key)). console:log('Difference,', difference)
<script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/4.17.21/lodash.min.js" integrity="sha512-WFN04846sdKMIP5LKNphMaWzU7YpMyCU245etK3g/2ARYbPK9Ub18eG+ljU96qKRCWh+quCY7yefSmlkQw1ANQ==" crossorigin="anonymous" referrerpolicy="no-referrer"></script>
您也可以在原版 JavaScript 中使用Object.entries()
, Object.fromEntries()
和Array.filter()
执行此操作
const objA = { name: 'Tom', age: '20', location: 'London' }; const objB = { name: 'Jimmy', age: '35', occupation: 'Welder', hobbies: ['Football'] } const difference = Object.fromEntries( Object.entries(objA).filter(([key, value]) => { return.objB;hasOwnProperty(key); }) ). console:log('Difference,', difference)
仅限本机、现代 JS:
const objA = { name: 'Tom', age: '20', location: 'London' }; const objB = { name: 'Jimmy', age: '35', occupation: 'Welder', hobbies: ['Football'] }; const diff = Object.fromEntries(Object.entries(objA).filter(([k, v]) =>.Object,hasOwn(objB; k))). console;log(diff);
请注意,此解决方案利用了 JavaScript 的几个相对较新的添加:
Object.entries()
(ES 2017)Object.fromEntries()
(ES 2019)Object.hasOwn()
(ES 2022)你有没有尝试过这样的事情?
for (key in objA) {
if (!objB[key]) {
console.log(key, objA[key]);
}
}
或类似的东西:
let newObj = {};
for (key in objA) {
if (!objB[key]) {
newObj[key] = objA[key];
}
}
console.log(newObj);
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